我如何传递url参数来形成值? [英] How do I pass url parameter to form value?

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问题描述

表单中有这个隐藏字段

 < input type =hiddenname =dir_typevalue =tshirt > 

网址参数

  / dir?type = tshirt 
/ dir?type = books
/ dir?type = posters

等等。



现在我硬编码 value =tshirts但我如何获取相关页面的参数?



我找到了几个页面



感谢您的帮助。
$ b

更新



通过systempuntoout回答完美地工作,但我决定不使用模板来解决问题。对于有类似问题的任何人,将url参数传递给这样的表单效果很好:

 < form name = submit_formaction =/ directorysubmithandlermethod =postonSubmit =return validate_form()> 
title:< input type =textname =titlesize = 50>< br />>
url:< input type =textname =urlsize = 50>< br />
< input type =hiddenname =dir_typevalue =%s)>
< input type =submitvalue =submit>
< / form>%self.request.get(type))


解决方案

类型值传递给视图:

  class Directory(webapp.RequestHandler):
def get(self):
....
merchandise_type = self .request.get(type,)
items = Item.all()
items.filter(type =,merchandise_type)
path = os.path.join( os.path.dirname(__ file__),'dir_details.html')
self.response.out.write(template.render(path,{'type':merchandise_type}))

b。类型值添加到隐藏字段:

 < input type =hiddenname =dir_typevalue ={{type}}> 

c。取得 dir_type value在你的发布处理器中:

  class DirectorySubmitHandler(webap p.RequestHandler):
def post(self):
user = users.get_current_user()
merchandise_type = self.request.get(dir_type,)
dir_type = merchandise_type
if user:
item = Item()
item.title = self.request.get(title)
item.url = self.request.get( url)
item.type = self.request.get(dir_type)
item.user_who_liked_this_item = user
item.put()
self.redirect(/ dir?type =%s%
self.request.get(dir_type))
else:
self.redirect(users.create_login_url(self.request.uri))


The form has this hidden field

<input type="hidden" name="dir_type" value="tshirt">

url parameters are

/dir?type=tshirt
/dir?type=books
/dir?type=posters

and so on.

Now I hard coded value="tshirts" but how do I get parameter for the relevant page?

I found several pages like this dealing with similar topics but I did not understand how this is done.

Thanks for your help.

UPDATE

The answer by systempuntoout works perfectly but I decided to solve the problem without using templates. And for anyone who has a similar question, passing the url parameter to the form like this works well:

<form name="submit_form" action="/directorysubmithandler" method="post" onSubmit="return validate_form()">
title: <input type="text" name="title" size=50><br />
url: <input type="text" name="url" size=50><br />
<input type="hidden" name="dir_type" value="%s")>
<input type="submit" value="submit">
</form>""" % self.request.get("type"))                      

解决方案

a. pass the type value to the view:

class Directory(webapp.RequestHandler):
    def get(self):
       ....
       merchandise_type = self.request.get("type", "")
       items = Item.all()
       items.filter("type =", merchandise_type)
       path = os.path.join(os.path.dirname(__file__), 'dir_details.html')
       self.response.out.write(template.render(path,{'type':merchandise_type}))

b. add the type value to the hidden field:

<input type="hidden" name="dir_type" value="{{ type }}">

c. get the dir_type value in your post handler:

class DirectorySubmitHandler(webapp.RequestHandler):
    def post(self):
        user = users.get_current_user()
        merchandise_type = self.request.get("dir_type", "")
        dir_type = merchandise_type
        if user:
            item = Item()
            item.title = self.request.get("title")
            item.url = self.request.get("url")
            item.type = self.request.get("dir_type")
            item.user_who_liked_this_item = user
            item.put()
            self.redirect("/dir?type=%s" %
self.request.get("dir_type"))
        else:
            self.redirect(users.create_login_url(self.request.uri)) 

这篇关于我如何传递url参数来形成值?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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