在OpenCL和Fortran中传递两个选项作为参数(CLFORTRAN) [英] Passing two options as arguments in OpenCL with Fortran (CLFORTRAN)
问题描述
当我的主机程序使用C语言时,我可以传递两个选项作为OpenCL函数的参数。例如,我可以像这样将两个
标志传递给 clCreateBuffer
函数:
clCreateBuffer(context,CL_MEM_READ_ONLY | CL_MEM_COPY_HOST_PTR,
sizeof(main_data),main_data,&err)
然而,我尝试在用Fortran编写的主机程序中执行相同的操作:
main_data = clCreateBuffer(context,CL_MEM_READ_ONLY | CL_MEM_COPY_HOST_PTR,&
sizeof(main_data),C_NULL_PTR,err)
我得到一个错误:
& | CL_MEM_COPY_HOST_PTR,size_in_bytes,C_NULL_PTR,ierr)
1
错误:参数列表中的语法错误(1)
我已经用CLFORTRAN成功编译了一些其他程序,但是每当我尝试传递两个标志,例如 CL_MEM_READ_ONLY | CL_MEM_COPY_HOST_PTR
我得到上述错误。
C按位或
不能在Fortran中使用。你必须使用 +
。 ior()
函数也可能工作,但我会使用 +
*。它的工作原理是因为常量的值通常设计为只有一个 1
位,并且每次都位于不同位置。
*如果您使用 +
,您可能不会添加同一个标志两次,它的标志会被错误地计算。 b
When my host program is in C language I can pass two options as an argument of an OpenCL function. For example, I can pass two
flags to the clCreateBuffer
function like this:
clCreateBuffer(context, CL_MEM_READ_ONLY | CL_MEM_COPY_HOST_PTR, sizeof(main_data), main_data, &err)
However, when I try to do the same in a host program written in Fortran:
main_data=clCreateBuffer(context, CL_MEM_READ_ONLY | CL_MEM_COPY_HOST_PTR, & sizeof(main_data), C_NULL_PTR, err)
I get an error:
& |CL_MEM_COPY_HOST_PTR, size_in_bytes,C_NULL_PTR,ierr)
1
Error: Syntax error in argument list at (1)
I have successfully compiled some other programs with CLFORTRAN, but whenever I try to pass two flags like CL_MEM_READ_ONLY | CL_MEM_COPY_HOST_PTR
I get the above error.
The C bitwise or |
cannot be used in Fortran. You have to use +
. The ior()
function would probably also work, but I would use +
*. It works because the valued of the constants are normally designed in such a way that they have only one 1
bit and every time at a different position.
*If you do use +
you may not add the same flag twice, it flags would be computed incorrectly.
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