在Fortran中，DATA INF / 1.D + 300 /是什么意思？ [英] What does DATA INF/1.D+300/ mean in Fortran?

问题描述

<$ p $

D

DATA INF / 1.D + 300 /

INF的值是多少？

解决方案

D 表示× 10 1.e + 300 中的 e c $ c>，但它是双精度的。





DOUBLE PRECISION 语句只是将3个变量定义为类型 double 。

DATA 语句

  DATA X / Y / 
  

转换为

  X = Y; 
  

在C＃中。因此，你得到

  double INF = 1.e + 300，DMIN，D12; 
  

既然 INF 这么大，我相信它意思是Infinity，在这种情况下，最好使用 real IEEE infinity （ double INF = double.PositiveInfinity，... ）。

I'm translating some Fortran to our C# app and I'm trying to figure out what a bit of Fortran means at the top of a function.

  DOUBLE PRECISION INF, DMIN, D12

  DATA INF/1.D+300/

What would the value of INF be?

解决方案

The D means "× 10^???", or commonly known as the e in 1.e+300 in C#, but it's for double precision.

The DOUBLE PRECISION statement just defines 3 variables to be of type double.

The DATA statement

DATA X/Y/

translates to

X = Y;

in C#. Hence you get

double INF = 1.e+300, DMIN, D12;

Since INF is so large I believe it means "Infinity", in that case it's better to use the real IEEE infinity (double INF = double.PositiveInfinity, ...).

这篇关于在Fortran中，DATA INF / 1.D + 300 /是什么意思？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！