在Fortran中查找满足条件的数组中最小值的[索引] [英] Finding [index of] the minimal value in array which satisfies a condition in Fortran

问题描述

我正在查找大于特定数字的数组中的最小值。我发现了 这个讨论 ，其中我不明白。有 MINLOC ，但它看起来不像我想要的那么多，尽管我没有解析给定示例中传递给它的参数。 （也可以使用循环来做到这一点，但它可能很笨拙。）

解决方案

你可能想 MINVAL 。

如果你的数组是说，

  array =（/ 21,52,831,46,125,68,7 ，8,549,10 / 
  

你想找到大于65的最小值，

  variable = minval（array，mask =（array> 65））
  

这显然会给68。

I am looking for a minimal value in an array which is larger than a certain number. I found this discussion which I don't understand. There is MINLOC, but it looks like it does not do as much as I would like on its own, though I didn't parse the arguments passed to it in the given examples. (It is also possible to do this using a loop but it could be clumsy.)

解决方案

You probably want MINVAL.

If your array is say,

array = (/ 21, 52, 831, 46, 125, 68, 7, 8, 549, 10 /)

And you want to find the minimum value greater than say 65,

variable = minval(array, mask=(array > 65))

which would obviously give 68.

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