如何在HTML页面上显示来自FTP服务器的图像？ [英] How to display images from FTP server on HTML page?

问题描述

我尝试为FTP服务器显示图像建立一个图像库。 FTP服务器需要密码认证。我扫描文件成功，但图像不显示在页面上，并通过点击参考页面询问用户名和密码。

  $ content =''; 
 $ ftp_server =255.122.111.111; 
 $ ftp_user =user_name; 
 $ ftp_pass =密码; 
 
 $ conn_id = ftp_connect（$ ftp_server）或死（无法连接到$ ftp_server）; 
 $ b $ if if（@ftp_login（$ conn_id，$ ftp_user，$ ftp_pass））{
 $ content。=< br />连接为$ ftp_user @ $ ftp_server\\\
 ; 
} else {
 $ content。=< br />无法以$ ftp_user \\\
连接; 
} 
 
 $ files = ftp_nlist（$ conn_id，$ dir）; 
 foreach（$ files为$ file_name）
 {
 $ content。='
< div> 
< a href =ftp：//'.$ftp_server.'/'.'filefile_name。'> 
< img src =ftp：//'.$ftp_server.'/'.$file_name。'width =150height =150> 
< / a> 
< / div>'; 
} 
  

我需要做那些图片是在页面上显示的吗？

解决方案

您可以准备一个脚本（例如 getimage.php ），根据请求…

• 从FTP服务器获取图像文件到一个（二进制）字符串变量中，就像在脚本中一样，然后


• 正确地准备图像标题，就像下面的代码片段一样，
  （另见
• 打印（二进制）图像字符串。
  

在HTML代码中插入通常的 标签。

getimage.php 脚本。手动提取图像类型：

  //从FTP服务器获取图像内容到$ binary 
 // $二进制文件现在包含图像文本
 // Then .... 
 
 header（'Content-type：'。image_file_type_from_binary（$ binary））; 
 echo $ binary; 
 
函数image_file_type_from_binary（$ binary）{
 if（
！preg_match（
'/ \\\A（？:( \xff\xd8\xff ）|（GIF8 [79]一个）|（\x89PNG\x0d\x0a）|（BM）|（\x49\x49（？：\x2a\x00 | \x00\x4a） ）|（FORM。{4} ILBM））/'，
 $ binary，$ hits 
）
）{
 return'application / octet-stream'; 
} 
 $ type = array（
 1 =>'image / jpeg'，
 2 =>'image / gif'，
 3 => 'image / png'，
 4 =>'image / x-windows-bmp'，
 5 =>'image / tiff'，
 6 =>'image / x -ilbm'，
）; 
 return $ type [count（$ hits） -  1]; 
} 
  

I try to build an image gallery for display images from FTP server. FTP server requires password authentication. I am scan files successful, but image don't display on page and by clicking on reference page ask user name and password.

$content = '';
$ftp_server = "255.122.111.111";
$ftp_user = "user_name";
$ftp_pass = "password";

$conn_id = ftp_connect($ftp_server) or die("Couldn't connect to $ftp_server"); 

if (@ftp_login($conn_id, $ftp_user, $ftp_pass)) {
    $content .= "<br />Connected as $ftp_user@$ftp_server\n";
} else {
    $content .= "<br />Couldn't connect as $ftp_user\n";
}

$files = ftp_nlist($conn_id, $dir);
foreach($files as $file_name)
{
    $content.=  '
         <div>
            <a href="ftp://'.$ftp_server.'/'.$file_name.'">
            <img src="ftp://'.$ftp_server.'/'.$file_name.'"    width="150" height="150">
           </a>
         </div>';
}

What I need to do that images are have been displayed on page?

解决方案

You could prepare a script (e.g. getimage.php) that, upon request…

• gets the image file from the FTP server into a (binary) string variable, like in your script, then
• prepares the image header correctly, like in the snippet below,
  (also see this link from stackoverflow)
• prints the (binary) image string.

In the HTML code insert the usual tags.

Follows a snippet of the getimage.php script. The image type is extracted manually:

// Get the image contents from FTP server into $binary
// $binary contains image text now
// Then ....

header('Content-type: ' . image_file_type_from_binary($binary));
echo $binary;

function image_file_type_from_binary($binary) {
  if (
    !preg_match(
        '/\A(?:(\xff\xd8\xff)|(GIF8[79]a)|(\x89PNG\x0d\x0a)|(BM)|(\x49\x49(?:\x2a\x00|\x00\x4a))|(FORM.{4}ILBM))/',
        $binary, $hits
    )
  ) {
    return 'application/octet-stream';
  }
  $type = array (
    1 => 'image/jpeg',
    2 => 'image/gif',
    3 => 'image/png',
    4 => 'image/x-windows-bmp',
    5 => 'image/tiff',
    6 => 'image/x-ilbm',
  );
  return $type[count($hits) - 1];
}

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