delphi形式与多实例使用 [英] delphi Form with multi instance use
问题描述
我有一个FTP上传器项目,它使用运行时创建的表单开始上传到多个FTP服务器(使用Indy),我的问题如下(我真的需要你的帮助)。
$ b
在表单上,我放置了一个IdFTP组件+上传按钮+名为FTPSrvAdrs和SrcFile + TrgFolder的公共属性,如下所示:
<$ p $ > code> type
TFtpUploader = class(TForm)
IdFTP:TIdFTP;
StartUpload:TButton;
UploadProgress:TProgressBar;
程序StartUploadClick(发件人:TObject);
procedure FormClose(Sender:TObject; var Action:TCloseAction);
private
FFtpSrvAdrs:String;
FSrcFile:String;
FTargetFtpFld:String;
过程StartMyUpload();
过程SetFtpAdrs(const value:string);
过程SetSrcFile(const value:string);
过程SetTargetFtpFld(const value:string);
{私有声明}
public
{公共声明}
属性FtpAdrs:字符串读取FFtpSrvAdrs写入SetFtpAdrs;
属性SourceFile:字符串读取FSrcFile写入SetSrcFile;
属性TargetFtpFld:读取的字符串FTargetFtpFld写入SetTargetFtpFld;
end;
var
FtpUploader:TFtpUploader;
实现
过程TFtpUploader.StartUploadClick(发件人:TObject);
begin
StartMyUpload();
end;
过程TFtpUploader.SetFtpAdrs(const value:string);
begin
FFtpSrvAdrs:= value;
end;
过程TFtpUploader.SetSrcFile(const value:string);
begin
FSrcFile:= value;
end;
过程TFtpUploader.SetTargetFtpFld(const value:string);
begin
FTargetFtpFld:= value;
end;
程序TFtpUploader.StartMyUpload;
var
FtpUpStream:TFileStream;
begin
ftpUpStream:= TFileStream.create(FSrcFile,fmopenread)
使用IdFTP尝试
开始
Host:= FFtpSrvAdrs;
用户名:='MyUserName';
密码:='MyPassword';
end;
IdFTP.Connect(true,1200)
IdFTP.Passive:= true;
IdFTP.ChangeDir(FTargetFtpFld)
IdFTP.Put(ftpUpStream,FSrcFile,false);
终于
ftpUpStream.Free;
end;
end;
procedure TFtpUploader.FormClose(Sender:TObject; var Action:TCloseAction);
begin
操作:= caFree;
end;
这个表单将在RunTime上创建(4次= 4个按钮将像这样分开启动它:
在主表单中我有这个程序:
程序MainForm.UploadTo(FTPSrv,SrcFile,FtpTargetFld:String);
var
FUploadFrm:TFtpUploader;
begin
FUploadFrm:= TFtpUploader.Create(nil);
if (FUploadFrm)then
begin
FUploadFrm.FtpAdrs:= FTPSrv;
FUploadFrm.SourceFile:= SrcFile;
FUploadFrm.TargetFtpFld:= FtpTargetFld;
FUploadFrm.Show ;
end;
end;
程序MainForm.Button1Click(Sender:TObject);
begin
UploadTo('MyFtpSrv_1','MySrcFile_1', 'MyFtpTargetFld_1');
end;
procedure MainForm.Button2Click(Sender:TObject);
begin
UploadTo( MyFtpSrv_2’ , MySrcFile_2’ , MyFtpTargetFld_2’ );
end;
//与其他2个按钮相同
FtpUploader表单被创建/打开(4个实例),问题是当我点击StartUpload按钮时,所有这4个实例都没有启动FTP上传过程,但我必须等待每个上传过程完成(完成),另一个将自动启动,这意味着并非所有的上传过程都是在同一时间开始的。
谢谢。
用于某些非阻塞后台库(基于事件或基于完成端口)的Indy库,或者使程序成为多线程(使用它自己的一堆问题,如用户单击按钮20次或关闭表单在运行中甚至关闭程序)。
基于 http://otl.17slon.com/book/doku.php?id=book:highlevel:async 它可以看起来像这样:
TFtpUploader = class(TForm)
private
CanCloseNow:boolean;
...
procedure TFtpUploader.FormClose(Sender:TObject; var Action:TCloseAction);
开始
如果Self.CanCloseNow
则操作:= caFree
else操作:= caIgnore;
end;
程序TFtpUploader.MyUploadComplete;
begin
Self.CanCloseNow:= True;
Self.Close;
end;
程序TFtpUploader.StartMyUpload;
begin
Self.CanCloseNow:= false;
Self.Enabled:= False;
Self.Visible:= True;
Application.ProcessMessages;
Parallel.Async(
过程
var
FtpUpStream:TFileStream;
begin
ftpUpStream:= TFileStream.create(FSrcFile,fmopenread)
使用IdFTP尝试
开始
Host:= FFtpSrvAdrs;
用户名:='MyUserName';
密码:='MyPassword';
Connect true,1200)
被动:= true;
ChangeDir(FTargetFtpFld)
//直到上传
// //才不会给德尔福一个机会处理按钮
//按下其他窗体
Put(ftpUpStream,FSrcFile,false);
end;
finally
ftpUpStream.Free;
结束;
结束
,
Parallel.TaskConfig.OnTerminated(
过程(const task:IOmniTaskControl)
begin
MyUploadComplete;
end;
);
end;
或者你可以使用简单的AsyncCalls库 http://andy.jgknet.de/blog/bugfix-units/asynccalls-29-asynchronous -function-calls /
i've an FTP uploader project that uses a form created on run time to start uploading to multiple FTP Servers ( using Indy ) , my issue is as follows ( and i really need your help ) .
On a Form i put an IdFTP Component + an Upload button + public properties named FTPSrvAdrs and SrcFile + TrgFolder like this way :
type
TFtpUploader = class(TForm)
IdFTP: TIdFTP;
StartUpload:TButton;
UploadProgress:TProgressBar;
procedure StartUploadClick(Sender: TObject);
procedure FormClose(Sender: TObject; var Action: TCloseAction);
private
FFtpSrvAdrs:String;
FSrcFile:String;
FTargetFtpFld:String;
Procedure StartMyUpload();
procedure SetFtpAdrs(const value:string);
procedure SetSrcFile(const value:string);
procedure SetTargetFtpFld(const value:string);
{ Private declarations }
public
{ Public declarations }
property FtpAdrs:string read FFtpSrvAdrs write SetFtpAdrs;
property SourceFile:string read FSrcFile write SetSrcFile;
property TargetFtpFld:string read FTargetFtpFld write SetTargetFtpFld;
end;
var
FtpUploader: TFtpUploader;
implementation
procedure TFtpUploader.StartUploadClick(Sender: TObject);
begin
StartMyUpload();
end;
procedure TFtpUploader.SetFtpAdrs(const value: string);
begin
FFtpSrvAdrs:=value;
end;
procedure TFtpUploader.SetSrcFile(const value: string);
begin
FSrcFile:=value;
end;
procedure TFtpUploader.SetTargetFtpFld(const value: string);
begin
FTargetFtpFld:=value;
end;
procedure TFtpUploader.StartMyUpload;
var
FtpUpStream: TFileStream;
begin
ftpUpStream:= TFileStream.create(FSrcFile, fmopenread)
try
with IdFTP do begin
Host:= FFtpSrvAdrs;
Username:='MyUserName';
Password:='MyPassword';
end;
IdFTP.Connect(true, 1200)
IdFTP.Passive:= true;
IdFTP.ChangeDir(FTargetFtpFld)
IdFTP.Put(ftpUpStream,FSrcFile, false);
finally
ftpUpStream.Free;
end;
end;
procedure TFtpUploader.FormClose(Sender: TObject; var Action: TCloseAction);
begin
Action:=caFree;
end;
This Form will be created on RunTime ( 4 times = 4 buttons will launch it separately like this way :
in the main form i've this procedure :
Procedure MainForm.UploadTo(FTPSrv,SrcFile,FtpTargetFld:String);
var
FUploadFrm:TFtpUploader;
begin
FUploadFrm:=TFtpUploader.Create(nil);
if assigned(FUploadFrm) then
begin
FUploadFrm.FtpAdrs:=FTPSrv;
FUploadFrm.SourceFile:=SrcFile;
FUploadFrm.TargetFtpFld:=FtpTargetFld;
FUploadFrm.Show;
end;
end;
procedure MainForm.Button1Click(Sender: TObject);
begin
UploadTo('MyFtpSrv_1','MySrcFile_1','MyFtpTargetFld_1');
end;
procedure MainForm.Button2Click(Sender: TObject);
begin
UploadTo('MyFtpSrv_2','MySrcFile_2','MyFtpTargetFld_2');
end;
// same with other 2 buttons
the FtpUploader form is Created / Opened ( 4 instances ) ,The ISSUE IS when i click on StartUpload button the FTP upload process is not started on all these 4 instances , but i've to wait each upload process is done ( finished ) and the other will auto-start , that means not all upload processes are started in same time .
Thank you .
It seems you have to either change Indy library for some non-blocking in-background library (event based or completion port based), or to make your program multi-threading (with it's own bunch of problems like user clicking a button 20 times or closing the form while the process is going, or even closing the program on the run).
Based on http://otl.17slon.com/book/doku.php?id=book:highlevel:async it can look anything like this:
TFtpUploader = class(TForm)
private
CanCloseNow: boolean;
...
procedure TFtpUploader.FormClose(Sender: TObject; var Action: TCloseAction);
begin
if Self.CanCloseNow
then Action := caFree
else Action := caIgnore;
end;
procedure TFtpUploader.MyUploadComplete;
begin
Self.CanCloseNow := True;
Self.Close;
end;
procedure TFtpUploader.StartMyUpload;
begin
Self.CanCloseNow := false;
Self.Enabled := False;
Self.Visible := True;
Application.ProcessMessages;
Parallel.Async(
procedure
var
FtpUpStream: TFileStream;
begin
ftpUpStream:= TFileStream.create(FSrcFile, fmopenread)
try
with IdFTP do begin
Host:= FFtpSrvAdrs;
Username:='MyUserName';
Password:='MyPassword';
Connect(true, 1200)
Passive:= true;
ChangeDir(FTargetFtpFld)
// this does not return until uploaded
// thus would not give Delphi a chance to process buttons
// pressed on other forms.
Put(ftpUpStream,FSrcFile, false);
end;
finally
ftpUpStream.Free;
end;
end
,
Parallel.TaskConfig.OnTerminated(
procedure (const task: IOmniTaskControl)
begin
MyUploadComplete;
end;
);
end;
Or you can use simplier AsyncCalls library http://andy.jgknet.de/blog/bugfix-units/asynccalls-29-asynchronous-function-calls/
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