从void函数返回 [英] Returning from a void function

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本文介绍了从void函数返回的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述



Which is more correct way to return from function:

void function() {
  // blah some code
}

OR

void function() {
  // blah some code
  return;
}






第二种方式的基本原理:


Rationale for second way:


  1. 它可以更清楚地表达开发人员的意图。

  2. 它有助于在预编译时检测函数结束:
  1. It expresses developer intentions more clearly.
  2. It helps detecting function end at pre-compile time:

假设你有这样的场景 - 你有一堆函数,你必须在这些函数的末尾注入一些代码。但出于某些原因,您不希望/或不能修改如此巨大的功能。你能做些什么? 返回&例如: macro >

Suppose you have such scenario- you have bunch of functions and you must inject some code at the end of those functions. But for some reasons you don't want / or can't modify such huge amount of functions. What can you do about that ? Return & macro comes into play, for example:

#include<stdio.h>

#define MAX_LINES 1000
#define XCAT(a,b) a##b
#define CAT(a,b) XCAT(a,b)
#define return returns[__LINE__] = 1;\
        if (returns[__LINE__])\
           {printf("End of function on %d line.\n",__LINE__);}\
        int CAT(tmp,__LINE__); \
        if ((CAT(tmp,__LINE__)=returns[__LINE__], returns[__LINE__] = 0, CAT(tmp,__LINE__)))\
              return

static int returns[MAX_LINES];


void function1(void) {
    return;
}

void function2(void) {
    return;
}

int main()
{
    function1();
    function2();

    return 0;
}


推荐答案

随你选。提供空的 return; 语句允许从某处返回 void 函数中的 return 除了结束之外。没有其他理由我相信。

Neither is more correct, so take your pick. The empty return; statement is provided to allow a return in a void function from somewhere other than the end. No other reason I believe.

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