文件打开功能，Try& Python 2.7.1除外 [英] File Open Function with Try & Except Python 2.7.1

问题描述

def FileCheck(fn):       
       try:
           fn=open("TestFile.txt","U") 
       except IOError: 
           print "Error: File does not appear to exist."
       return 0 

我试着做一个函数来检查一个文件存在，如果不存在，则应打印错误消息并返回0。为什么不能正常工作???

I'm trying to make a function that checks to see if a file exists and if doesn't then it should print the error message and return 0 . Why isn't this working???

推荐答案

如果您想从内部返回，您需要缩进返回0除了块。
另外，你的论点并没有做太多的事情。而不是分配文件句柄，我假设你想让这个函数能够测试任何文件？

You'll need to indent the return 0 if you want to return from within the except block. Also, your argument isn't doing much of anything. Instead of assigning it the filehandle, I assume you want this function to be able to test any file? If not, you don't need any arguments.

def FileCheck(fn):
    try:
      open(fn, "r")
      return 1
    except IOError:
      print "Error: File does not appear to exist."
      return 0

result = FileCheck("testfile")
print result

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