Python:通过名称和kwargs一起传递参数 [英] Python: Passing parameters by name along with kwargs

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问题描述

在python中,我们可以这样做:

  def myFun1(one ='1',two ='2'): 
...

然后我们可以调用函数并按名称传递参数:



myFun1(two ='two',one ='one')



我们也可以这样做:

  def myFun2(** kwargs):
print kwargs.get('one','nothing here')

myFun2(所以我想知道是否有可能将两种方法结合起来:

  def myFun3(name,lname,** other_info):
...

myFun3(lname ='Someone',name ='myName',city ='cityName',otherInfo ='blah')

一般情况下我们可以做什么样的组合?

感谢和抱歉我这个愚蠢的问题

p>

解决方案

总体思路是:

  def func(arg1,arg2,...,kwarg1 = default,kwarg2 = default,...,* args,** kwargs):
。 ..

您可以使用尽可能多的那些。 * ** 会'吸收'任何剩余的价值,否则不会说明。



位置参数(不带默认值提供)不能由关键字给出,非默认参数不能跟在默认参数后面。



注意Python 3还增加了通过在 * 之后指定关键字参数的功能:

  def func(arg1,arg2,* args,kwonlyarg = default):
...

您也可以单独使用 * def func(a1,a2,*,kw = d) code>)这意味着没有参数被捕获,但之后的任何参数都是关键字。

因此,如果你在3.x中,你可以产生你想要的行为:

  def myFun3(*,name,lname,** other_info):
.. 。

这可以通过 name 进行调用, lname 作为关键字。



请注意,这是一个联合国通常的界面,这可能会让用户恼火 - 我只会在非常具体的用例中使用它。



在2.x中,您需要手动创建解析 ** kwargs


In python we can do this:

def myFun1(one = '1', two = '2'):
    ...

Then we can call the function and pass the arguments by their name:

myFun1(two = 'two', one = 'one')

Also we can do this:

def myFun2(**kwargs):
    print kwargs.get('one', 'nothing here')

myFun2(one='one')

So i was wondering if it is possible to combine both methods like:

def myFun3(name, lname, **other_info):
    ...

myFun3(lname='Someone', name='myName', city='cityName', otherInfo='blah')

In general what combinations can we do?

Thanks and sorry for my silly question

解决方案

The general idea is:

def func(arg1, arg2, ..., kwarg1=default, kwarg2=default, ..., *args, **kwargs):
    ...

You can use as many of those as you want. The * and ** will 'soak up' any remaining values not otherwise accounted for.

Positional arguments (provided without defaults) can't be given by keyword, and non-default arguments can't follow default arguments.

Note Python 3 also adds the ability to specify keyword-only arguments by having them after *:

def func(arg1, arg2, *args, kwonlyarg=default):
    ...

You can also use * alone (def func(a1, a2, *, kw=d):) which means that no arguments are captured, but anything after is keyword-only.

So, if you are in 3.x, you could produce the behaviour you want with:

def myFun3(*, name, lname, **other_info):
    ...

Which would allow calling with name and lname as keyword-only.

Note this is an unusual interface, which may be annoying to the user - I would only use it in very specific use cases.

In 2.x, you would need to manually make this by parsing **kwargs.

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