def anti_vowel - codecademy(python) [英] def anti_vowel - codecademy (python)
问题描述
定义一个名为anti_vowel的函数,它接受一个字符串text作为输入并返回删除了所有元音的文本。
这是我的尝试:
def anti_vowel(text):
vowels = [a,A,e,E,i,I对于文本中的字符
text_input.append(char)
av =$
text_input = [] [char for char in text_input if char not in vowels]
return av
我的代码返回输入为单独的字符。
这是我得到的错误:
糟糕,请再试一次。您的函数在anti_vowel上失败(Hey look Words!)。它返回['','H','y','','l','k','','W','r','d','s','!']当它应该返回Hy lk Wrds!。
有人可以请我指出正确的方向吗?
>>> =h2_lin>解决方案
tgt ='这是一些带元音的文字'
>>>元音='aeiou'
>>> ''.join(e for tgt if e.lower()not in vowels)
'Ths smtxt wth vwls'
或者,如评论中所指出的,使用实际列表理解加入是更好的:
> >> ''.join([e for tgt if e.lower()not in vowels])
's s sm txt wth vwls'
I am a bit stuck on creating the anti_vowel definition:
Define a function called anti_vowel that takes one string, text, as input and returns the text with all of the vowels removed
This is my attempt:
def anti_vowel(text):
vowels=["a","A","e","E","i","I","o","O","u","U"]
text_input=[""]
for char in text:
text_input.append(char)
av = [char for char in text_input if char not in vowels]
return av
My code returns the input as separate characters.
This is the error I get:
Oops, try again. Your function fails on anti_vowel("Hey look Words!"). It returns "['', 'H', 'y', ' ', 'l', 'k', ' ', 'W', 'r', 'd', 's', '!']" when it should return "Hy lk Wrds!".
Could someone please point me in the right direction?
Consider:
>>> tgt='This is some text with vowels'
>>> vowels='aeiou'
>>> ''.join(e for e in tgt if e.lower() not in vowels)
'Ths s sm txt wth vwls'
Or, as pointed out in comments, using an actual list comprehension inside join is better:
>>> ''.join([e for e in tgt if e.lower() not in vowels])
'Ths s sm txt wth vwls'
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