将字符串更改为javascript中的函数(而不是eval) [英] changing string to a function in javascript (not eval)

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问题描述

  var foo =function(){alert('meee');}; 
foo();

我已经尝试了上述方法,但它不起作用,有没有其他方法可以在不使用eval?



thnx

解决方案

要使用<$正如Anders所说,直接使用c $ c> Function 构造函数。所有参数都是字符串。最后一个参数是函数的主体,任何主要参数都是函数所用参数的名称。



借用Anders的例子,

  var multiply = new函数(x,y,return x * y); 

将会像写作一样

  var multiply = function(x,y){
return x * y
}

在你的情况下,你有function(){alert('meee');},你想把它保存为函数var foo

  var fn =function(){ alert('meee');}; 
var foo = new Function(return(+ fn +))();
foo();
// alertsmeee

函数 eval eval 运行在私人范围内,而功能在全局范围内运行。

  var x =haha,y =hehe; 

函数test(){
var x = 15,y = 34;
eval(alert('eval:'+ x +','+ y));
new Function(alert('Func:'+ x +','+ y))();
}

test();

// eval:15,34
// Func:haha,hehe

不要试图在控制台中运行它,你会得到一个欺骗结果(控制台使用 eval )。将它写入< script> 标记并将其加载到浏览器中将会给出真正的结果。


var foo = "function (){ alert('meee'); }";
foo();

I have tried the above but it does not work is there any other way to execute that function without using eval?

thnx

解决方案

you want to use the Function constructor directly, as Anders said. All arguments are strings. The last argument is the body of the function, any leading arguments are the names of the arguments the function takes.

To borrow from Anders' example,

var multiply = new Function("x", "y", "return x * y");

would be like writing

var multiply = function (x,y) {
  return x * y
}

In your case, you have "function (){ alert('meee'); }" and you want to save it as a function to var foo.

var fn = "function (){ alert('meee'); }";
var foo = new Function("return ("+fn+")")();
foo();
// alerts "meee"

The difference between Function and eval is eval runs in the private scope, while Function runs in the global scope.

var x="haha", y="hehe";

function test () {
  var x=15, y=34;
  eval("alert('eval: ' + x + ', ' + y)");
  new Function("alert('Func: ' + x + ', ' + y)")();
} 

test();

// eval: 15, 34
// Func: haha, hehe

Don't try to run it in the console, you'll get a deceiving result (consoles use eval). Writing it in a <script> tag and loading it in the browser will give the true result.

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