三元运算符返回值 - Java / Android [英] Ternary operator to return value- Java/Android

查看:909
本文介绍了三元运算符返回值 - Java / Android的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

刚刚从php切换到Java



我遇到以下问题



我想重写

  if(usrname.equals(username)&&(passwd.equals(password))){
return true;
}
else {
return false;

$ / code>

as

 (usrname.equals(username)&& passwd.equals(password))?返回true:返回false; 

不工作(语法错误)
但是,

  int a = 1; 
int b = 2;
int minVal = a< b? a:b;

正在工作

为什么三元运算符在依据某些条件返回值时行为不正确

编辑

  return(usrname.equals(username)&& passwd.equals(password));如果它返回布尔值,

可能是解决方案。



< (usrname.equals(username)&& passwd.equals(password))?可以说我需要

 返回member:返回guest; 


解决方案

您可以做

  return(usrname.equals(username)&& passwd.equals(password))?真假; 

true false 可以被你想要的任何返回值替换。如果它只是布尔值,那么你可以完全避免使用三元运算符。只要做

  return(usrname.equals(username)&& passwd.equals(password)); 


Just switched to Java from php

I encountered following issue

I want to rewrite

if(usrname.equals(username) && (passwd.equals(password))){
    return true;
}
else{
    return false;
}

as

(usrname.equals(username) && passwd.equals(password) )? return true : return false;

it is not working(syntax error) however,

int a=1;
int b=2;
int minVal = a < b ? a : b;

is working

Why ternary operator are not behaving correctly while returning value depending on some condition

EDIT

return  (usrname.equals(username) && passwd.equals(password)); 

could be solution if it return boolean .

lets say i need

 (usrname.equals(username) && passwd.equals(password) )? return "member": return "guest";

解决方案

You can do

return (usrname.equals(username) && passwd.equals(password) )?  true : false;

true and false can be replaced by any return value you want. If it is just boolean then you can avoid ternary operator altogether. Just do

return  (usrname.equals(username) && passwd.equals(password));

这篇关于三元运算符返回值 - Java / Android的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆