C ++ Concatinating __func__和const char文字 [英] C++ Concatinating __func__ and const char literal

问题描述

我试图在C ++中concordate __ func__和文字字符串，并且我在GCC（有或没有C ++ 11 standart）上出错。例如，像这样：

  #include  
 int main（void）
 {
 printf（％s，__func__try＃1 \\\
）; 
 printf（__ func__try＃2 \\\
）; 
返回0; 
} 
  

看起来像__ func__实际上不是字符串文字宏。有人知道为什么会发生这种情况，也许是解决这个问题的方法吗？

解决方案

从技术上讲， __ func__ 是一个预定义的标识符。它是从不实现为一个宏。

它的类型为 static const char __func __ [] std :: string 中。

使用

printf（％s try＃1 \\\
，__func __）;

代替。

I am trying to concatinate __ func__ and literal string in C++ and I am getting an error on GCC (with or without of C++11 standart). Like, for example, here:

#include <cstdio>

int main(void)
{
        printf("%s", __func__ " try #1\n");
        printf(__func__ " try #2\n");
        return 0;
}

Looks like __ func__ is not actually a string literal macros. Does anyone knows why that is happening and, maybe, way to solve it?

解决方案

Technically, __func__ is a predefined identifier. It's never implemented as a macro.

It has the type static const char __func__[] and so therefore you can't concatenate it the way you have. Of course, you can add it to a std::string though.

Use

printf("%s try #1\n", __func__);

instead.

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