在C中使用不同的库 [英] Using a different library in C
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问题描述
我从头开始编写一个程序,可以计算用户输入的大小写字母和空格。从那时起,我发现那些特定函数的代码已经在另一个库中被预先编写了!我的问题是,如何使用
isupper(int c)
, islower(int c)
,和 isspace(int c)
C>文件ctype.h 。
#include< stdio.h>
int main(void){
int iochar,numdigits = 0,numlower = 0,numupper = 0,numwhites = 0;
printf(请输入一个短语:\\\
\\\
); ((iochar = getchar())!= EOF)
if((iochar =='')||(iochar =='\ t' )||(iochar =='\\\
'))
{
numwhites ++;
putchar(iochar); ((iochar> ='0')&&(iochar< ='9'))
{
numdigits ++;
}
else
if
putchar(iochar); (('''= iochar)&&(iochar< ='z'))
{
numlower ++;
}
else
putchar(iochar-32); ((A'< = iochar)&&(iochar< ='Z'))
{
numupper ++;
}
else
if
putchar(iochar);
}
else
putchar(iochar);
}
printf(%d个白色字符,%d个数字,numwhites,numdigits);
printf(%d小写字母已被转换为,numlower);
printf(大写和%d大写。),numupper);
printf(\\\
\\\
);
return 0;}
解决方案 $ p
$ b
$ b
#include< stdio.h>
#include< ctype.h>
$ b $ int main(int argc,char ** argv){
int iochar,numdigits = 0,numlower = 0,numupper = 0,numwhites = 0;
printf(请输入一个短语:\\\
\\\
); ((iochar = getchar())!= EOF){
//在必要时增加计数
if(isspace(iochar)){
numwhites ++;
} else if(isdigit(iochar)){
numdigits ++;
} else if(islower(iochar)){
numlower ++;
iochar = toupper(iochar);
} else if(isupper(iochar)){
numupper ++;
}
//总是发生这种情况,不要把它放在if
putchar(iochar)中;
}
printf(%d个白色字符,%d个数字,numwhites,numdigits);
printf(%d小写字母已被转换为,numlower);
printf(大写和%d大写。),numupper);
printf(\\\
\\\
);
返回0;
}
I just coded from scratch a program that would count the upper and lowercase letters and blank spaces of whatever the user input. Since then I found out that code for those specific functions have already been prewritten in another library! My question is, how can all the code that I have written below be simplified with the use of
isupper(int c)
, islower(int c)
, and isspace(int c)
which are defined in ctype.h
.
#include <stdio.h>
int main(void){
int iochar, numdigits=0, numlower=0, numupper=0, numwhites=0;
printf("Please enter a phrase:\n\n");
while((iochar=getchar())!=EOF)
{
if ((iochar==' ')||(iochar=='\t')||(iochar=='\n'))
{
numwhites++;
putchar(iochar);
}
else
if((iochar>='0')&&(iochar<='9'))
{
numdigits++;
putchar(iochar);
}
else
if(('a'<=iochar)&&(iochar<='z'))
{
numlower++;
putchar(iochar-32);
}
else
if(('A'<=iochar)&&(iochar<='Z'))
{
numupper++;
putchar(iochar);
}
else
putchar(iochar);
}
printf("%d white characters, %d digits, ",numwhites,numdigits);
printf("%d lowercase have been converted to ",numlower);
printf("uppercase and %d uppercase.\n",numupper);
printf("\n\n");
return 0;}
解决方案
Here is it written better and cleaned up:
#include <stdio.h>
#include <ctype.h>
int main(int argc, char **argv) {
int iochar, numdigits=0, numlower=0, numupper=0, numwhites=0;
printf("Please enter a phrase:\n\n");
while ((iochar=getchar()) != EOF) {
// increase counts where necessary
if (isspace(iochar)) {
numwhites++;
} else if (isdigit(iochar)) {
numdigits++;
} else if (islower(iochar)) {
numlower++;
iochar = toupper(iochar);
} else if (isupper(iochar)) {
numupper++;
}
// this happens always, don't put it in the if's
putchar(iochar);
}
printf("%d white characters, %d digits, ", numwhites, numdigits);
printf("%d lowercase have been converted to ", numlower);
printf("uppercase and %d uppercase.\n", numupper);
printf("\n\n");
return 0;
}
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