茉莉花测试：如何通过测试函数中调用的函数调用？ [英] Jasmine test: how to call through function that is called in tested function?

问题描述

我尝试用Jasmine测试JavaScript函数。它看起来像这样：

  show：function（）{
 this.work（）; 
 var mod = new Module（）; 
 mod.doSomething（）; 
 
 $ / code> 

我现在正在测试 work（） code>在 show（）中调用，这是没有问题的。但是，在 mod.doSomething（）中发生错误。这使我的测试失败，虽然它实际上已经通过。我能做些什么来防止mod.doSomething被调用或至少被执行。是否有像 callThrough（）用于未使用的函数调用？

我唯一的想法是编写一个全局从任何地方都可以设置为true或false的变量。然后，我扩展了 mod.doSomething（）函数，以便在此变量设置为true时不被调用。现在我可以简单地将变量设置为true，如果我不想在测试时执行此函数。但我认为必须有更好的解决方案。任何人都可以帮助我吗？

解决方案

这不适用于标准茉莉花做法。方法 show（）应该将一个模块作为参数....然后它可以在 doSomething（） ...

I try to test a JavaScript function with Jasmine. It looks like this:

show: function(){
    this.work();
    var mod = new Module();
    mod.doSomething();
}

I am now testing if work() is called in show(), which is no problem. But then an error occurs in mod.doSomething(). This makes my test fail although it actually passed. What can I do to prevent mod.doSomething to be called or at least executed. Is there something like callThrough() for nonused function calls?

The only idea I had was to write a global variable that can be set true or false from everywhere. Then I extend the mod.doSomething() function for not to be called if this variable is set true. Now I can simply set the variable to true, if I do not want this function to be executed while testing. But I think there must be a better solution. Can anybody help me?

解决方案

this is not testable with "standard" jasmine-practices. the method show() should take a module as parameter.... then it would be testable with a spy on doSomething()...

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