Python分割列表 [英] Python split for lists

问题描述

如果我们在python中有一个 list strings 并且想要基于一些特殊的<$ c创建子列表










$ b $ p> l = [data，more data，，data 2，more data 2，danger，，date3，lll]
p = split_special（l，）


会生成：

  p = [[data，more data]，[data 2，more data 2，danger]，[ date3，lll]] 
  

解决方案

itertools.groupby 是一种方法（就像往常一样）：

 >>> l = [data，more data，，data 2，more data 2，danger，，date3，lll] 
>>> ; from itertools import groupby 
>>> groupby（l，lambda x：x ==）
 >>> [list（group）for k，group by groupby（l，lambda x：x ==）如果不是k] 
 [['data'，'more data']，['data 2'，'更多数据2'，'危险']，['date3'，'lll']] 
  

我们甚至可以因为这种特殊情况而作弊：

 >>> [数组'（数据2）'，'更多数据2'，'危险' ]，['date3'，'lll']] 
  

If we have a list of strings in python and want to create sublists based on some special string how should we do?

For instance:

l = ["data","more data","","data 2","more data 2","danger","","date3","lll"]
p = split_special(l,"")

would generate:

p = [["data","more data"],["data 2","more data 2","danger"],["date3","lll"]]

解决方案

itertools.groupby is one approach (as it often is):

>>> l = ["data","more data","","data 2","more data 2","danger","","date3","lll"]
>>> from itertools import groupby
>>> groupby(l, lambda x: x == "")
<itertools.groupby object at 0x9ce06bc>
>>> [list(group) for k, group in groupby(l, lambda x: x == "") if not k]
[['data', 'more data'], ['data 2', 'more data 2', 'danger'], ['date3', 'lll']]

We can even cheat a little because of this particular case:

>>> [list(group) for k, group in groupby(l, bool) if k]
[['data', 'more data'], ['data 2', 'more data 2', 'danger'], ['date3', 'lll']]

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