jQuery是一个monad [英] Is jQuery a monad
问题描述
我在某处读过jQuery是monad,并且这个答案显示underscore.js库中的链函数不是monad(但是是comonad)。和回答这个类似的,表明这是monoid。
那么,jQuery是monad吗?
不符合单子法。 jQuery
是一个很大的 API
,所以在统计上,它不太可能是意外的一元。因此,我非常怀疑整个 jQuery
API可以满足monad规则(即jQuery是monad)。这并不意味着一个给定的(非常有限的)子集可能不满足它们,但是整个API可能包含违反操作的不安全操作因为没有人似乎提供了证据表明API的全部或部分符合法律,所以我建议我们应该假设它的确如此直到提供证据为止。
必须显示:
return
(将值提取到jQuery monad中)?
绑定
,用于将计算粘合在一起?
然后,鉴于jQuery API的其他部分,可能违反哪些规则?例如,我可以通过调用其他API函数之一来破坏 bind
吗?
参考资料: cl / 2011/12 / jquery-is-not-a-monad /> jQuery不是monad
I read somewhere that jQuery is a monad and this answer shows that chain function in underscore.js library is not a monad (but comonad). And answer to this which is similar, shows that is monoid.
So, is jQuery a monad?
Most APIs do not satisify the monad laws. jQuery
is a large API
, so statistically, it is unlikely to be "accidentally" monadic. As a result I am pretty skeptical that the jQuery
API as a whole could satisfy the monad laws (i.e. that "jQuery is a monad").
This doesn't mean that a given (very restricted) subset might not satisfy them, but the API as a whole is likely to contain "unsafe" operations that would violate the laws when used, breaking the abstraction.
Since no one seems to have offered evidence that the API in whole or part satisifies the laws, I suggest we should assume it does not, until evidence is provided.
It must be shown:
- what jQuery operation corresponds to
return
(lifting a value into the jQuery monad)? - what jQuery operation corresponds to
bind
, for gluing computations together? - how do the left-, right- and associativity laws hold over those operations?
And then, what law violations are possible given the rest of the jQuery API? Can I, for example, break the bind
by calling one of the other API functions?
References:
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