如何隐式链接库？ [英] How to implicitly link libraries?

问题描述

我有一个名为A.a的库，它的.hpp文件叫做A.hpp。当程序需要使用这个库时，它们#includeA.hpp，并像这样链接到它：g ++ test1.cpp A.a -o test1。我希望能够像这个g ++ test1.cpp -o test1一样编译它，而不需要在那里明确地键入A.a，就像我不需要明确地将我的程序与iostream链接。我可以如何实现这一点？

I have a library called A.a, and its .hpp file called A.hpp. When programs need to use this library, they #include "A.hpp", and get linked to it like this: g++ test1.cpp A.a -o test1. I'd like to be able to only compile it like this g++ test1.cpp -o test1, without explicitly typing A.a in there, just like I don't need to explicitly link my program with iostream. How can I achieve this?

推荐答案

它可以在Visual C ++上完成（编译器可以在对象文件中嵌入一些链接器选项，请求链接一个图书馆是可能的）。

It can be done on Visual C++ (the compiler can embed some linker options in object files, requests to link a library being one of those that are possible).

海湾合作委员会（据我所知，铛）没有这样的功能。您必须在命令行上提供这些库;没有办法绕过它（构建工具在技术上并不是一种解决方法;它们也将库放到他们用来运行链接器的命令行中）。

Gcc (and, to my knowledge, clang) do not have such a feature. You have to provide the libraries on the command line; there is no way around it (build tools are not technically a way around it; they also put the libraries onto the command lines they use to run the linker).

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