strncpy和strcat不工作,我认为他们会c ++ [英] strncpy and strcat not working the way I think they would c++
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问题描述
我有一个任务来自己实现一个字符串对象,并且当试图连接两个这样的字符串时,它现在被卡住了。我想我会走这条路:
执行:
#include< iostream>
#include< cstring>
使用namespace std;
int main(){
int index = 6; //插入位置
char * temp = new char [21];
char * mystr = new char [21 + 7 +1];
char * insert = new char [7];
temp =你好,这是一个测试;
insert =world;
strncpy(mystr,temp,index);
strcat(mystr + 7,insert);
strcat(mystr,temp + index);
mystr [21 + 6] ='\0';
cout<< mystr:<< mystr<< ENDL;
返回0;
}
代码在使用可视化工作室时在Hello之后打印乱码,但在使用g ++(有警告),为什么差异?
解决方案
您将c本机概念与c ++混合使用。不是一个好主意。
这更好:
#include <&的iostream GT;
#include< string> //不是cstring
using namespace std;
int main(){
int index = 6; //插入位置
字符串temp =你好,这是一个测试;
string insert =world;
string mystr = temp.substr(0,index)+ insert + temp.substr(index);
cout<< mystr:<< mystr<< ENDL;
返回0;
}
I have an assignment to implement a string object ourselves, and am currently stuck when trying to concatenate two such strings. I figured I would go this route:
- allocate big enough space to hold
- insert beginning of holding string into new space up to index using strncpy(this part works)
- cat on the string I am inserting
- cat on the remainder of the holding string
Implementation:
#include <iostream>
#include <cstring>
using namespace std;
int main(){
int index = 6;//insertion position
char * temp = new char[21];
char * mystr = new char[21 + 7 +1];
char * insert = new char[7];
temp = "Hello this is a test";
insert = " world ";
strncpy(mystr, temp, index);
strcat(mystr + 7, insert);
strcat(mystr, temp + index);
mystr[21 + 6] = '\0';
cout << "mystr: " << mystr << endl;
return 0;
}
that code prints out gibberish after Hello when using visual studios, but works when using g++ (with warnings), why the discrepancy?
解决方案
You're mixing native c concepts with c++. Not a good idea.
This is better:
#include <iostream>
#include <string> // not cstring
using namespace std;
int main(){
int index = 6;//insertion position
string temp = "Hello this is a test";
string insert = "world ";
string mystr = temp.substr(0, index) + insert + temp.substr(index);
cout << "mystr: " << mystr << endl;
return 0;
}
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