呼叫运营商<<在gdb中 [英] calling operator<< in gdb

问题描述

你如何从gdb中调用运算符<<（std :: ostream& os，const ClassX& x）？

换句话说，你如何在gdb中打印一个对象？

call std :: cout 或调用操作符<<（std :: cout，x）似乎不适用于我！

有什么想法？

解决方案

我发现的唯一方法是：

  call'operator<<（std :: ostream&，myclass&）'（mycout，c）
  

由于某些原因， std :: cout 对于gdb是不可见的，所以我不得不求助于像这样创建我自己的：

  std :: ostream mycout（std :: cout.rdbuf（））; 
  

您没有说明想要这样做的任何理由，但不会打印你的变量更容易？

如果这是绝对必须的，你可以在你的类中有一个 Print 方法，并从 operator< 然后从gdb调用对象的 Print 方法。

请注意stdout可能在gdb中被缓冲，所以除非您以某种方式重定向它，否则您将看不到任何输出。

请参阅这篇来自gdb的邮件存档关于这个问题的讨论。

How do you call operator<<(std::ostream &os, const ClassX &x) from inside gdb ?

In other words, how do you print an object in gdb ?

call std::cout<<x or call operator<<(std::cout, x) don't seems to work for me!

Any ideas?

解决方案

The only way I found was this:

call 'operator<<(std::ostream&, myclass&)'(mycout, c)

Since std::cout wasn't visible to gdb for some reason, I had to resort to creating my own like this:

std::ostream mycout(std::cout.rdbuf());

You haven't stated any reasons for wanting to do this but won't print yourvariable be easier?

If this is an absolute must you could have a Print method in your class and call that from operator<< and then call the Print method on your object from gdb.

Do take note that stdout is probably buffered in gdb so you won't be seeing any output unless you redirect it somehow.

See this discussion from gdb's mailing archive regarding this issue.

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