使用非路径名称在gdb中启动应用程序 [英] Launch application in gdb with non-path name

问题描述

我试图在GDB中启动遗留应用程序，并且它要求它的 argv [0] 值不包含除字母数字字符以外的任何内容。 b
$ b

每当我在GDB中启动程序时，它似乎会在运行程序之前将名称扩展为完整路径，所以出现类似的错误（因为它无法处理斜杠）：

找不到/ home / user / myapp ...

是否可以运行在GDB中有一个相对路径的程序，所以它只会看到myapp？

解决方案

Gdb通常运行目标命令shell命令行

 
 exec 程序路径名  program_arguments  
 

但它有一个 set exec-wrapper 命令会将其更改为

 
 exec  exec_wra pper  program_pathname  program_arguments  
 

exec_wrapper em>通常是另一个命令，但它可以是 exec 命令接受的任意字符串。

许多shell （bash，zsh，ksh93）为 exec 命令支持 -a 选项来设置argv [0]。

所以，如果你的shell支持 exec -a ，你可以执行以下操作来调用 / home / user / myapp 与argv [0] == myapp ：

 （gdb）set exec-wrapper -a myapp 
  

I am trying to launch a legacy application in GDB, and it requires that it's argv[0] value not contain anything other than alphanumeric characters.

Whenever I launch the program in GDB it seems that it expands the name to be the full path before running the program, so I get an error like (because it can't deal with the slashes):

"Cannot find /home/user/myapp ..."

Is it possible to run a program in GDB with a relative path, so that it will just see "myapp"?

解决方案

Gdb normally runs target commands using the shell command line

    exec program_pathname program_arguments

But it has a set exec-wrapper command that will change this to

    exec exec_wrapper program_pathname program_arguments

The exec_wrapper is often another command, but it can be any arbitrary string that the exec command accepts.

Many shells (bash, zsh, ksh93) support a -a option to the exec command to set argv[0].

So, if your shell supports exec -a, you can do the following to invoke /home/user/myapp with argv[0]==myapp:

(gdb) set exec-wrapper -a myapp

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