我是否错过了某些东西，或者做了可变参数分析Arrays.asList？ [英] Am I missing something, or do varargs break Arrays.asList?

问题描述

  private void activateRecords（long [] stuff）{
 ... 
 api.activateRecords（Arrays.asList（specIdsToActivate））; 
} 
  

不应该对Arrays.asList的这个调用返回一个龙 S'相反，它返回一个 List< long []>

  public静态< T>列表与LT; T> asList（T ... a）
  

方法签名与结果一致，可变参数引发整个数组放入列表中。它与 new ArrayList（）相同。 list.add（myArray）是的，我知道它的用意是这样的： Arrays.asList（T t1，T t2，T t3）


我猜我在做什么，而不是可变参数形式，为什么我不能只有我的旧asList方法（至少我认为这是它是如何工作的）将会把内容放到一个列表中？任何其他干净这样做的方式？

解决方案

这是因为long []和Long []是不同的类型。



在第一种情况下T是long []，在第二个T中是Long。

如何解决这个问题？首先不要使用long []？

  private void activateRecords(long[] stuff) {
    ...
    api.activateRecords(Arrays.asList(specIdsToActivate));
  }

Shouldn't this call to Arrays.asList return a list of Longs? Instead it is returning a List<long[]>

public static <T> List<T> asList(T... a)

The method signature is consistent with the results, the varargs throws the entire array into the list. It's the same as new ArrayList(); list.add(myArray) And yes, I know it's meant to be used like this: Arrays.asList(T t1, T t2, T t3)

I guess what I'm getting at, is instead of the varargs form, why can't I just have my old asList method (at least I think this is how it used to work) that would take the contents and put them individually into a list? Any other clean way of doing this?

解决方案

That's because long[] and Long[] are different types.

In the first case T is long[], in the second T is Long.

How to fix this? Don't use long[] in the first place?

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