使用System.Type作为< T>在运行时使用Json.Net进行反序列化 [英] Using System.Type as <T> at runtime when deserializing with Json.Net
问题描述
public static Task< p>串GT; Convert(string payload,Type type)
{
JsonSerializerSettings settings = new JsonSerializerSettings()。Configure(); //< ---拉取扩展方法来处理自定义类型
return JsonConvert .SerializeObject(JsonConvert.DeserializeObject< type>(payload),settings));
}
上面的代码不能编译。接下来,我使用约翰斯基特的回答到2011年类似的问题
$ b
public static string Convert(string payload,Type type)
{
JsonSerializerSettings settings = new JsonSerializerSettings()。Configure();
//这与方法表中另一个DeserializeObject重载冲突
MethodInfo method = typeof(JsonConvert).GetMethod(DeserializeObject,new [] {typeof(string)});
method = method.MakeGenericMethod(type);
object [] arguments = new object [1];
参数[0] =有效载荷;
string result =(string)method.Invoke(null,arguments);
返回JsonConvert.SerializeObject(result,settings);
$ / code>
有一个非泛型重载和一个泛型重载方法表查找失败。我能够通过调用我的函数(非模糊)来解决这个问题,类似于下面。
public static string Convert (字符串有效载荷,类型类型)
{
JsonSerializerSettings settings = new JsonSerializerSettings()。Configure();
//这与方法表中的DeserializeObject的另一个重载冲突
MethodInfo method = typeof(TestConverter).GetMethod(TestThis,new [] {typeof(string)});
method = method.MakeGenericMethod(type);
object [] arguments = new object [1];
参数[0] =有效载荷;
string result =(string)method.Invoke(null,arguments);
返回JsonConvert.SerializeObject(result,settings);
public static T TestThis< T>(string s)
{
return JsonConvert.DeserializeObject< T>(s);
}
但是,我现在回到我的自定义转换扩展方法被忽略的位置因为反序列化器忽略了我的Type类型。
这甚至是可能的。当然,我可以使用类似于以下的反序列化版本:
object result = JsonConvert.DeserializeObject(payload);
然而,我的练习是使用 任何提示? 你不需要跳过篮球。 I have a process that needs to be able to call on a function in the following manner. The code above does not compile. Next, I used John Skeet's answer to a 2011 question similar to mine. There is an overload non-generic and a generic overload with the same name and the method table lookup fails. I was able to get around that problem by calling into my function (non-ambiguous) similar to below. However, I am now back to where my custom conversion extension methods are being ignored because the de-serializer is ignoring my Type type. Is this even possible. Of courseI could use the de-serialization version similar to: However, my exercise is to use the Any tips? You do not need to jump through hoops.
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JsonConvert.DeserializeObject
具有非通用的重载,它接受类型
。
public static Task< string> Convert(string payload,Type type)
{
JsonSerializerSettings settings = new JsonSerializerSettings()。Configure(); //< ---拉取扩展方法来处理自定义类型
return JsonConvert .SerializeObject(JsonConvert.DeserializeObject(payload,type),settings));
}
public static Task<string> Convert(string payload, Type type)
{
JsonSerializerSettings settings = new JsonSerializerSettings().Configure();//<--- Pull in extension methods to handle custom types
return JsonConvert.SerializeObject(JsonConvert.DeserializeObject<type>(payload), settings));
}
public static string Convert(string payload, Type type)
{
JsonSerializerSettings settings = new JsonSerializerSettings().Configure();
//This clashes with another overload of DeserializeObject in the method table
MethodInfo method = typeof(JsonConvert).GetMethod("DeserializeObject", new[] { typeof(string) });
method = method.MakeGenericMethod(type);
object[] arguments = new object[1];
arguments[0] = payload;
string result = (string)method.Invoke(null, arguments);
return JsonConvert.SerializeObject(result, settings);
}
public static string Convert(string payload, Type type)
{
JsonSerializerSettings settings = new JsonSerializerSettings().Configure();
//This clashes with another overload of DeserializeObject in the method table
MethodInfo method = typeof(TestConverter).GetMethod("TestThis", new[] { typeof(string) });
method = method.MakeGenericMethod(type);
object[] arguments = new object[1];
arguments[0] = payload;
string result = (string)method.Invoke(null, arguments);
return JsonConvert.SerializeObject(result, settings);
}
public static T TestThis<T>(string s)
{
return JsonConvert.DeserializeObject<T>(s);
}
object result = JsonConvert.DeserializeObject(payload);
JsonConvert.DeserializeObject<T>(payload)
overload so that my converters can be invoked.JsonConvert.DeserializeObject
has a non-generic overload that accepts a Type
. public static Task<string> Convert(string payload, Type type)
{
JsonSerializerSettings settings = new JsonSerializerSettings().Configure();//<--- Pull in extension methods to handle custom types
return JsonConvert.SerializeObject(JsonConvert.DeserializeObject(payload, type), settings));
}