如何根据位置获得雅虎的诡计？ [英] How to get Yahoo's woeid by location?

问题描述

// Get woeid by lati/long
            HttpGet hg = new HttpGet(
                        "http://where.yahooapis.com/geocode?location=" + latlon + "&flags=J&gflags=R)");
            HttpClient hc = new DefaultHttpClient();
            HttpResponse weatherHR = hc.execute(hg);

            if (weatherHR.getStatusLine().getStatusCode() != HttpStatus.SC_OK) {
                if (DEBUG)
                    Utils.log("", "Location != HttpStatus.SC_OK");
                return null;
            }

我使用了这个API，它以前可以正常工作，但是它返回一个错误，今天，HttpStatus.SC_OK不正确。此API是否已关闭？谢谢。

I used this API and it work ok before, but It return a error since today, the HttpStatus.SC_OK is not OK. Has this API been closed? Thanks.

推荐答案

是的，它已关闭，请查看此处：
http://soup.metwit.com/post/47181933854/an-alternative-to-yahoo- weather-api

Yes, it's closed, give a look here: http://soup.metwit.com/post/47181933854/an-alternative-to-yahoo-weather-api

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