如何在android中发送数据到服务器 [英] how to send data to server in android

问题描述

我想在我的应用程序中循环发送经纬度。
这是使用GPS获取此参数的函数

  private void showLocation（Location location）{
 String latitude =Latitude：; 
 String longitude =Longitude：; 
 
 if（location！= null）{
 latitude + = location.getLatitude（）; 
 longitude + = location.getLongitude（）; 
 
 
  

我在网络中查找方法时，发现了一些但它不起作用，它已被弃用

  public void sendData（double latitude，double longitude）{
 HttpClient httpclient = new DefaultHttpClient（）; 
 HttpPost httppost = new HttpPost（http：//192.x.x.x：8080 / run / mypage.php）; 
尝试{
列表< NameValuePair> nameValuePairs = new ArrayList< NameValuePair>（2）; 
 
 nameValuePairs.add（new BasicNameValuePair（Latitude，Double.toString（latitude）））; 
 nameValuePairs.add（new BasicNameValuePair（Longitude，Double.toString（longitude）））; 
 httppost.setEntity（new UrlEncodedFormEntity（nameValuePairs））; 
 httpclient.execute（httppost）; 
 $ b $ catch（ClientProtocolException e）{
 // TODO自动生成的catch块
} catch（IOException e）{
 // TODO自动生成的catch块
 
 
 $ / code $ / pre 
 
 
预先致谢4帮助
 
解决方案
我建议您使用 OkHttp 图书馆的网络。你的例子可能是这样的
  private final OkHttpClient client = new OkHttpClient（）; 
 $ b $ public String sendData（double latitude，double longitude）{
 try {
 RequestBody formBody = new FormBody.Builder（）
 .add（Latitude，Double .toString（latitude））
 .add（Longitude，Double.toString（longitude））
 .build（）; 
 
 Request request = new Request.Builder（）
 .url（http://httpbin.org/post）
 .post（formBody）
。建立（）; 
 
响应响应= client.newCall（request）.execute（）; 
 return response.body（）。string（）; 
} catch（IOException e）{
 returnError：+ e.getMessage（）; 
 
 
  
不要忘记在 AsyncTask  
  class IOAsyncTask extends AsyncTask< Location，Void，String> {
 
 @Override 
 protected String doInBackground（Location ... params）{
 return sendData（params [0] .getLatitude（），params [0] .getLongitude（） ）; 
} 
 
 @Override 
保护无效onPostExecute（字符串响应）{
 Log.d（networking，response）; 
} 
} 
  
这可以是 onCreate 您的活动方法
 保护无效的onCreate（Bundle savedInstanceState）{
 super。的onCreate（savedInstanceState）; 
 setContentView（R.layout.activity_main）; 
 
位置current = new Location（）; 
 current.setLatitude（23.9569596）; 
 current.setLongitude（12.567567）; 
 
 new IOAsyncTask（）。execute（current）; 
} 
  
请注意我使用 http：// httpbin .org / post 作为远程地址，您必须替换为您的端点URL。在我的情况下，答复是： 
 
 
  {
args：{}，
data ：，
files：{}，
form：{
Latitude：23.9569596，
Longitude：12.567567
，
headers：{
Accept-Encoding：gzip，
Content-Length：39，
Content-Type： application / x-www-form-urlencoded，
Host：httpbin.org，
User-Agent：okhttp / 3.0.1
}，
json：null，
origin：xxx.xx.xxx.xx，
url：http://httpbin.org/post
 } 
  
 
I want to send latitude and longitude cyclically in my app.
This is the function which get this parameters using GPS
 private void showLocation(Location location) {
    String latitude = "Latitude: ";
    String longitude = "Longitude: ";

    if (location != null) {
        latitude += location.getLatitude();
        longitude += location.getLongitude();
}
}
I was looking methods in the web, I found some but it didn't work and it's deprecated
public void sendData(double latitude, double longitude){
    HttpClient httpclient = new DefaultHttpClient();
    HttpPost httppost = new HttpPost("http://192.x.x.x:8080/run/mypage.php");
    try {
        List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);

        nameValuePairs.add(new BasicNameValuePair("Latitude", Double.toString(latitude)));
        nameValuePairs.add(new BasicNameValuePair("Longitude", Double.toString(longitude)));
        httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
        httpclient.execute(httppost);

    } catch (ClientProtocolException e) {
        // TODO Auto-generated catch block
    } catch (IOException e) {
        // TODO Auto-generated catch block
    }
}
Thanks in advance 4 help
解决方案
I recommend you to use OkHttp library for networking. Your example could be something like this
private final OkHttpClient client = new OkHttpClient(); 

public String sendData(double latitude, double longitude){
    try {
        RequestBody formBody = new FormBody.Builder()
                .add("Latitude", Double.toString(latitude))
                .add("Longitude", Double.toString(longitude))
                .build();

        Request request = new Request.Builder()
                .url("http://httpbin.org/post")
                .post(formBody)
                .build();

        Response response = client.newCall(request).execute();
        return response.body().string();
    } catch (IOException e) {
        return "Error: " + e.getMessage();
    }
}
Don't forget to run networking code in an AsyncTask 
class IOAsyncTask extends AsyncTask<Location, Void, String> {

    @Override
    protected String doInBackground(Location... params) {
        return sendData(params[0].getLatitude(), params[0].getLongitude());
    }

    @Override
    protected void onPostExecute(String response) {
        Log.d("networking", response);
    }
}
And this could be the onCreate method of your activity
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    Location current = new Location("");
    current.setLatitude(23.9569596);
    current.setLongitude(12.567567);

    new IOAsyncTask().execute(current);
}
Please notice that I use http://httpbin.org/post as remote address, you must replace with your Endpoint URL. In my case the response is:
{
 "args": {}, 
 "data": "", 
 "files": {}, 
 "form": {
   "Latitude": "23.9569596", 
   "Longitude": "12.567567"
 }, 
 "headers": {
   "Accept-Encoding": "gzip", 
   "Content-Length": "39", 
   "Content-Type": "application/x-www-form-urlencoded", 
   "Host": "httpbin.org", 
   "User-Agent": "okhttp/3.0.1"
 }, 
 "json": null, 
 "origin": "xxx.xx.xxx.xx", 
 "url": "http://httpbin.org/post"
}


                        
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