使用PHP $ _GET更正超链接URL的语法 [英] Correct syntax for hyperlink URL with PHP $_GET

问题描述

我想知道如何将我网站上的信息放在我网站第一页的网址上，然后在下一页上使用 $ _ GET 来获取来自URL的变量。

I am wondering how I would put information from my website in the URL on the first page of my site, and then on the next page, use $_GET to get the variables from the URL.

我只是想把它放在< a href =mywebsite.com/page?name=$name> ;< / a> 如果我这样做，它会起作用吗？如果是这样，我将如何从URL中获取它？

I was just wanting to put it in a link like <a href="mywebsite.com/page?name=$name"></a> So would it work if I did it like that, and if it would, how would I get it from the URL?

推荐答案

do

<a href="http://mywebsite.com/page?name=<?php echo $name; ?>"></a>

并且在您的页面中，您可以使用以下名称：

And in your page, you could get the name as:

$name = $_GET['name'];

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