PHP包含（）GET属性（包括file.php？q = 1） [英] PHP include() with GET attributes (include file.php?q=1)

问题描述

我想要 include（）一个位于我的服务器上的php文件，以及额外的GET属性。
但它不起作用：

I want to include() a php file located on my server, with additional GET attributes. But it won't work:

include('search.php?q=1');

它给出的错误：

The error it gives:

PHP Warning:  include(): Failed opening './search.php?q=1' for inclusion

好像它试图打开一个字面上名为'search.php？q = 1'的文件，而不是打开'search.php'文件并发送GET属性。

Seems like it tries to open a file literally named 'search.php?q=1' instead of opening the 'search.php' file and sending it the GET attributes.

*请注意，如果我没有放置任何GET属性，它就会工作：

*Note that it does work if I don't put any GET attributes:

include('search.php');

推荐答案

你不想这样做： d必须做一个http请求才能传递GET参数。您以这种方式调用的PHP脚本将运行在单独的PHP进程中。

You don't want to do this: You'd have to do a http request to be able to pass GET parameters. A PHP script you call in this way will run in a separate PHP process.

最佳方式是在本地包含文件：

The optimal way is to include the file locally:

include('search.php');

并手动传递任何参数，例如

and to pass any parameters to it manually, like e.g.

$q = "1";
include('search.php');  // expects `$q` parameter

或者更干净地将所有内容放在 search.php 放入一个可以用参数调用的函数或类中：

or, more cleanly, putting whatever you have in search.php into a function or class that you can call with a parameter:

include('search.php');  // defines function my_search($q)  
my_search(1);       

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