从字符串中提取数字? Java的 [英] Extract numbers from a string?! Java
问题描述
对于我的程序,我正在尝试着想如何才能让用户输入一串数字作为字符串;提取每个数字的空格并将它们解析为整数。
PS我仍然是编程语言的新手,所以请以我能理解的方式解释,谢谢。 / p>
这是我到目前为止:
用户可以输入一系列数字,例如:15 31 94 87 108 11 7 63 79
public int [] getNumbers(){
扫描器读取器=新的扫描仪(System.in);
String inputStr = reader.nextLine();
int [] a = new int [10];
String [] numb = new String [10];
int space = inputStr.indexOf();
int length = inputStr.length();
for(int x = 0; x
numb [x] = inputStr.substring(0,space);
inputStr = inputStr.substring(space + 1);
int num = Integer.parseInt(numb [x]);
System.out.println(num);
a [x] = num;
}
return a;
}
此时获取第一个数字,然后缩短字符串。我将如何去寻找下一个数字,并结束它,因为它出界了?谢谢。
您可以使用字符串的拆分方法来完成此操作:
String [] numbers = numb.split();
int [] a = new int [numbers.length];
for(int x = 0; x a [x] = Integer.parseInt(numbers [x]);;
}
For my program I am trying to figure how I can go about taking a series of number as string entered by the user; extract each number at spaces and parse them into integers.
P.S I am still a newbie to the programming languages so please explain in a way that I can understand, thanks.
This is what I have so far:
A user may input a series of number like this: 15 31 94 87 108 11 7 63 79
public int [] getNumbers (){
Scanner reader = new Scanner (System.in);
String inputStr = reader.nextLine();
int[] a = new int [10];
String[] numb = new String [10];
int space = inputStr.indexOf (" ");
int length = inputStr.length();
for (int x = 0; x < numb.length; x++){
numb [x] = inputStr.substring (0, space);
inputStr = inputStr.substring (space+1);
int num = Integer.parseInt (numb[x]);
System.out.println (num);
a[x] = num;
}
return a;
}
This at the moment get the first number, then shorten the string. How would I go about finding the next number and ending it with out having it going out of bound ? thank you.
You can do this using string's split method:
String[] numbers = numb.split(" ");
int[] a = new int [numbers.length];
for (int x = 0; x < numb.length; x++){
a[x] = Integer.parseInt (numbers[x]);;
}
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