PHP使用GET方法 [英] PHP uses GET method

问题描述

 < form action =addScript.phpmethot =POSTenctype =多部分/格式数据> 
< tr> 
< td>产品标题：< / td>< td>< input type =textname =titleid =title/>< / td> 
< / tr> 
< tr> 
< td>产品描述：< / td>< td>< textarea rows =5cols =40name =descriptionid =description>< / textarea> < / TD> 
< / tr> 
< tr> 
< td>价格（USD $）：< / td>< td>< input type =textname =priceid =price/>< / td> 
< / tr> 
< tr> 
< td>个人资料图片：< / td>< td>< input type =filename =profilepicid =profilepic/>< / td> 
< / tr> 
< tr> 
 
< td>其他图片：< / td>< td> 
< div id =picturesstyle =border：1px solid black;>< table> 
< tr>< td> 1< / td>< td>< input type =fileid =pic1name =pic1/>< / td> TR> 
< tr>< td> 2< / td>< td>< input type =fileid =pic2name =pic2/>< / td> TR> 
 tr< td> 3< td>< td>< input type =fileid =pic3name =pic3/>< / td>< TR> 
< / table> 
< / div> 
< / td> 
< / tr> 
< tr> 
< td>< / td>< td>< input type =submitvalue =Add/>< / td> 
< / form> 
  

问题是，即使我使用方法POST，当它调用addScript.php时，使用的方法实际上是GET，我的链接是 www.domain.com/addScript.php?name= ..& description = ... etc。
如果我在php文件中使用 $ name = $ _ REQUEST ['title']; ，我得到这个错误：未定义的索引：title / home / domain /public_html/addScript.php on line 13 。我该如何解决这个问题？

编辑
这是我的PHP没有mysqli_connect（）;

$ b $

  $ name = $ _ POST ['title']; 
 $ description = $ _ POST ['description']; 
 $ price = $ _ POST ['price']; 
 $ profilePic = $ _ FILES ['profilepic'] ['name']; 
 $ path =images /; 
 
 //在图片/文件夹中移动图片并获得它们的路径
 $ pic1 = $ _ FILES ['pic1'] ['name']; 
 $ pictmp = $ _ FILES ['pic1'] ['tmp_name']; 
 $ moveResult = move_uploaded_file（$ pictmp，$ path）; 
 
 $ pic2 = $ _ FILES ['pic2'] ['name']; 
 $ pictmp = $ _ FILES ['pic2'] ['tmp_name']; 
 $ moveResult = move_uploaded_file（$ pictmp，$ path）; 
 
 $ pic3 = $ _ FILES ['pic3'] ['name']; 
 $ pictmp = $ _ FILES ['pic3'] ['tmp_name']; 
 $ moveResult = move_uploaded_file（$ pictmp，$ path）; 
 
 $ pic1Path = $ path。$ pic1; 
 $ pic2Path = $ path。$ pic2; 
 $ pic3Path = $ path。$ pic3; 
 
 //在数据库中插入信息
 $ sql =INSERT INTO产品（名称，说明，价格，profile_pic，pic1，pic2，pic3）
 VALUES 
 '$名'， '$说明'， '$价格'，$ profilePic， '$ pic1Path'， '$ pic2Path'， '$ pic3Path'）; 
 if（！mysqli_query（$ con，$ sql））{
 die（ERROR.mysqli_error（$ con））; 
} 
  

我总是收到这个错误

 错误您的SQL语法错误;请检查第3行
   $ b 
 重新编辑： 
 
 
 
现在我可以看到回复的确认，但它填充我的error_log这些错误，并在数据库中的列大多是空的。
  [05-Feb-2014 15:01 ：12 UTC] PHP注意：未定义的索引：在第13行的/home/domain/public_html/addScript.php中的标题
 [05-Feb-2014 15:01:12 UTC] PHP Notice：Undefined index：description in /home/domain/public_html/addScript.php on line 14 
 [05-Feb-2014 15:01:12 UTC] PHP注意：Undefined index：price in /home/domain/public_html/addScript.php on line 15 
 [05-Feb-2014 15:01:12 UTC] PHP注意：未定义的索引：profilepic in /home/domain/public_html/addScript.php on line 16 
 [05-Feb-2014 15 ：01：12 UTC] PHP注意：未定义索引：pic1在/home/domain/public_html/addScript.php在线20 
 [05-Feb-2014 15:01:12 UTC] PHP注意：未定义的索引：pic1 in /home/domain/public_html/addScript.php on line 21 
 [05-Feb-2014 15 PHP的注意：未定义的索引：pic2在/home/domain/public_html/addScript.php在线24 
 [05-Feb-2014 15:01:12 UTC] PHP公告：未定义索引：图2在/home/domain/public_html/addScript.php 25行
 [05-Feb-2014 15:01:12 UTC] PHP注意：未定义索引：pic3在/home/domain/public_html/addScript.php在线28 
 [05-Feb-2014 15:01:12 UTC] PHP注意：未定义的索引：pic3在/home/domain/public_html/addScript.php上线29 
  
 重新编辑  
 
 
 code> var_dump（$ _ REQUEST）; 在$ name之前的PHP文件中，并得到这个
  array（7）{[name] =>字符串（4）aaaa[description] =>字符串（7）aaaaaaa[price] =>字符串（3）555[profilepic] =>字符串（7）cr7.jpg[pic1] =>字符串（9）copac.jpg[pic2] => string（9）close.png[pic3] =>字符串（12）obiectiv.jpg} 1产品增加了
  
但是DB中的列仍为空。  
 
解决方案
您的表单中有错字。您键入 methot 而不是方法： 
 
 
 < form action =addScript.phpmethot =POSTenctype =multipart / form-data> 
  
应该是 
 
 < form action =addScript.phpmethod =POSTenctype =multipart / form-data> 
  
 更新  
 < 
 （'$ name'，'$ description'，'$价格'，$ profilePic'，'$ pic1Path'，'$ pic2Path'，'$ pic3Path'）; 
 ^^^^^ 
这里
  
应该是 
 
 （'$ name'，' $说明， '$价格'， '$ profilePic'， '$ pic1Path'， '$ pic2Path'， '$ pic3Path'）; 
 ^^^^^ 
这里
  
 
I have this form :
<form action="addScript.php" methot="POST" enctype="multipart/form-data">
            <tr>
                <td>Produt title : </td><td><input type="text" name="title" id="title" /></td>
            </tr>
            <tr>
                <td>Product description : </td><td><textarea rows="5" cols="40" name="description" id="description"></textarea></td>
            </tr>
            <tr>
                <td>Price (USD $) : </td><td><input type="text" name="price" id="price" /></td>
            </tr>
            <tr>
                <td>Profile Picture : </td><td><input type="file" name="profilepic" id="profilepic" /></td>
            </tr>
            <tr>

                <td>Other pictures : </td><td>
                <div id="pictures" style="border:1px solid black;"><table>
                <tr><td>1</td><td><input type="file" id="pic1" name="pic1" /></td></tr>
                <tr><td>2</td><td><input type="file" id="pic2" name="pic2" /></td></tr>
                <tr><td>3</td><td><input type="file" id="pic3" name="pic3" /></td></tr>
                </table>
            </div>
            </td>
        </tr>
        <tr>
            <td></td><td><input type="submit" value="Add" /></td>
        </form>
The problem is that even if I use method POST, when it calls addScript.php, the method used is actually GET and my link is www.domain.com/addScript.php?name=..&description=... etc.
And if I use $name=$_REQUEST['title']; in the php file , I get this error :Undefined index: title in /home/domain/public_html/addScript.php on line 13.How can I solution this?


EDIT
This is my PHP without the mysqli_connect();
$name=$_POST['title'];
  $description=$_POST['description'];
  $price=$_POST['price'];
  $profilePic=$_FILES['profilepic']['name'];
  $path="images/";

  //move picures in images/ folder and get their path
  $pic1=$_FILES['pic1']['name'];
  $pictmp=$_FILES['pic1']['tmp_name'];
  $moveResult=move_uploaded_file($pictmp, $path);

  $pic2=$_FILES['pic2']['name'];
  $pictmp=$_FILES['pic2']['tmp_name'];
  $moveResult=move_uploaded_file($pictmp, $path);

  $pic3=$_FILES['pic3']['name'];
  $pictmp=$_FILES['pic3']['tmp_name'];
  $moveResult=move_uploaded_file($pictmp, $path);

  $pic1Path=$path.$pic1;
  $pic2Path=$path.$pic2;
  $pic3Path=$path.$pic3;

//insert info in database
  $sql="INSERT INTO products ( name, description, price, profile_pic, pic1, pic2, pic3)
  VALUES 
  ('$name','$description','$price',$profilePic','$pic1Path','$pic2Path','$pic3Path')";
  if(!mysqli_query($con,$sql)){
    die("ERROR ".mysqli_error($con));
  }
And I always get this error 
ERROR You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near 'images/','images/','images/')' at line 3
Re-EDIT :

Now I can see the confirmation echoed, but it fills my error_log with these errors and the columns in the database are mostly empty .
[05-Feb-2014 15:01:12 UTC] PHP Notice:  Undefined index: title in /home/domain/public_html/addScript.php on line 13
[05-Feb-2014 15:01:12 UTC] PHP Notice:  Undefined index: description in /home/domain/public_html/addScript.php on line 14
[05-Feb-2014 15:01:12 UTC] PHP Notice:  Undefined index: price in /home/domain/public_html/addScript.php on line 15
[05-Feb-2014 15:01:12 UTC] PHP Notice:  Undefined index: profilepic in /home/domain/public_html/addScript.php on line 16
[05-Feb-2014 15:01:12 UTC] PHP Notice:  Undefined index: pic1 in /home/domain/public_html/addScript.php on line 20
[05-Feb-2014 15:01:12 UTC] PHP Notice:  Undefined index: pic1 in /home/domain/public_html/addScript.php on line 21
[05-Feb-2014 15:01:12 UTC] PHP Notice:  Undefined index: pic2 in /home/domain/public_html/addScript.php on line 24
[05-Feb-2014 15:01:12 UTC] PHP Notice:  Undefined index: pic2 in /home/domain/public_html/addScript.php on line 25
[05-Feb-2014 15:01:12 UTC] PHP Notice:  Undefined index: pic3 in /home/domain/public_html/addScript.php on line 28
[05-Feb-2014 15:01:12 UTC] PHP Notice:  Undefined index: pic3 in /home/domain/public_html/addScript.php on line 29
Re-Re-EDIT

I added var_dump($_REQUEST); in the PHP file before the $name and got this 
array(7) { ["name"]=> string(4) "aaaa" ["description"]=> string(7) "aaaaaaa" ["price"]=> string(3) "555" ["profilepic"]=> string(7) "cr7.jpg" ["pic1"]=> string(9) "copac.jpg" ["pic2"]=> string(9) "close.png" ["pic3"]=> string(12) "obiectiv.jpg" } 1 product added
But still columns in DB are empty.
解决方案
You have a typo in your form. You typed methot instead of method:
<form action="addScript.php" methot="POST" enctype="multipart/form-data">
should be
<form action="addScript.php" method="POST" enctype="multipart/form-data">
update

You're missing a quote in your SQL query:
('$name','$description','$price',$profilePic','$pic1Path','$pic2Path','$pic3Path')";
                                ^^^^^
                                 HERE  
should be
('$name','$description','$price','$profilePic','$pic1Path','$pic2Path','$pic3Path')";
                                ^^^^^
                                 HERE


                        
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