Parcelable和继承Android中 [英] Parcelable and inheritance in Android
本文介绍了Parcelable和继承Android中的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我Parcelable的实施工作不涉及继承的一个类。我找出最好的方式来实现接口问题的时候才来继承。比方说,我有这样的:
I got an implementation of Parcelable working for a single class that involves no inheritance. I have problems figuring out the best way to implement the interface when it come to inheritance. Let's say I got this :
public abstract class A {
private int a;
protected A(int a) { this.a = a; }
}
public class B extends A {
private int b;
public B(int a, int b) { super(a); this.b = b; }
}
问题是,这是贯彻落实Parcelable接口B中推荐的方式(以A?在他们两个人?怎么样?)
Question is, which is the recommended way to implement the Parcelable interface for B (in A? in both of them? How?)
推荐答案
下面是我最好的解决办法,我将很高兴从别人那有想过这个问题听。
Here is my best solution, I would be happy to hear from somebody that had a thought about it.
public abstract class A implements Parcelable {
private int a;
protected A(int a) {
this.a = a;
}
public void writeToParcel(Parcel out, int flags) {
out.writeInt(a);
}
protected A(Parcel in) {
a = in.readInt();
}
}
public class B extends A {
private int b;
public B(int a, int b) {
super(a);
this.b = b;
}
public static final Parcelable.Creator<B> CREATOR = new Parcelable.Creator<B>() {
public B createFromParcel(Parcel in) {
return new B(in);
}
public B[] newArray(int size) {
return new B[size];
}
};
public int describeContents() {
return 0;
}
public void writeToParcel(Parcel out, int flags) {
super.writeToParcel(out, flags);
out.writeInt(b);
}
private B(Parcel in) {
super(in);
b = in.readInt();
}
}
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