使用lapply的地块列表 [英] List of plots using lapply
问题描述
df <-as.data.frame(matrix(rnorm(50),ncol = 5))
名称(df)<-c(x1,x2,x3,x4,x5)
df1 <-seq_len(10)
ll < lapply(seq(1,5),function(i)qplot(df1,df [,i]))
`[.data.frame`(df,,i)中的错误:未定义的列选择
好吧,显然我在可重复的代码中犯了一个不幸的错误。它现在可以工作,但 ll
列表中的所有图都是同一个图。当我运行这个:
$ p $ do.call(grid.arrange,ll)
我收到以下图片:
所有地块都是一样的!这也是当我通过我的数据运行时获得的输出。
无论如何。您需要执行以下操作:
ll <-lapply(
seq(1,5),
函数(i)qplot(data = data.frame(y = df [,i]),df1,y)
)
这会迫使每个图表的y值更新。
在这个其他的讨论中 SO Post 。
I have been using lapply and sapply as my go-to functions recently. So far so good, but why the following code does not work baffles me.
df<-as.data.frame(matrix(rnorm(50),ncol=5))
names(df)<-c("x1","x2","x3","x4","x5")
df1<-seq_len(10)
ll<-lapply(seq(1,5), function(i) qplot(df1,df[,i]))
I get the error:
Error in `[.data.frame`(df, , i) : undefined columns selected
Ok, apparently I made quite an unfortunate mistake in my reproducible code. It works now, but all the plots in the ll
list are the same plot. When I run this:
do.call(grid.arrange,ll)
I get the following image:
All the plots are the same! This is also the output I get when I run this through my data.
There are problems with lazy evaluation, or something like it anyway. You need to do the following:
ll<-lapply(
seq(1,5),
function(i) qplot(data=data.frame(y=df[, i]), df1, y)
)
This will force the y values to be updated for each plot.
More discussion in this other SO Post.
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