Android的德codeR-＆GT;德code返回false的位图下载 [英] Android decoder->decode returned false for Bitmap download

问题描述

我已经开始得到一个

DEBUG/skia(xxxx): --- decoder->decode returned false 

问题上从Facebook，我在ImageViews使用一些个人资料图片。大多数工作完美，但每过一段时间我发现一个从来没有工作。

issue on a few profile images from Facebook that I use in ImageViews. Most work perfectly, but every once in a while I discover one that never works.

我编译我对Android 1.6的应用程序向后兼容的原因。

I am compiling my application against Android 1.6 for backward compatibility reasons.

我做了一些挖掘，发现了一些关于这个问题的线程。我已经使用了FlushedInputStream这里讨论：<一href="http://$c$c.google.com/p/android/issues/detail?id=6066">http://$c$c.google.com/p/android/issues/detail?id=6066

I did some digging and discovered a number of threads on the issue. I'm already using the FlushedInputStream discussed here: http://code.google.com/p/android/issues/detail?id=6066

Bitmap b = BitmapFactory.decodeStream(new FlushedInputStream(is));
imageView.setImageBitmap(b);

下面是这是造成我的麻烦的例子： <一href="http://profile.ak.fbcdn.net/hprofile-ak-snc4/hs269.snc3/23132_639284607_390_q.jpg">http://profile.ak.fbcdn.net/hprofile-ak-snc4/hs269.snc3/23132_639284607_390_q.jpg

Here's an example that's causing me trouble: http://profile.ak.fbcdn.net/hprofile-ak-snc4/hs269.snc3/23132_639284607_390_q.jpg

有人可以检查出的形象，帮我找出是什么导致了麻烦？

Can someone check out the image and help me figure out what's causing the trouble?

推荐答案

有一个在FlushedInputStream（是）一个错误。它失败的连接速度慢，但你可以试试我的神奇code，以解决它。

There is a bug in FlushedInputStream(is). it fails on slow connections but you can try my magical code to fix it.

Bitmap b = BitmapFactory.decodeStream(new FlushedInputStream(is));
imageView.setImageBitmap(b);

你的方法之外创建一个静态类

create a static class outside your method

 static class FlushedInputStream extends FilterInputStream {
        public FlushedInputStream(InputStream inputStream) {
            super(inputStream);
        }

        @Override
        public long skip(long n) throws IOException {
            long totalBytesSkipped = 0L;
            while (totalBytesSkipped < n) {
                long bytesSkipped = in.skip(n - totalBytesSkipped);
                if (bytesSkipped == 0L) {
                    int b = read();
                    if (b < 0) {
                        break;  // we reached EOF
                    } else {
                        bytesSkipped = 1; // we read one byte
                    }
                }
                totalBytesSkipped += bytesSkipped;
            }
            return totalBytesSkipped;
        }
    }

在这里你去..现在你不会有任何问题。

and here you go.. now you will not have any problem.

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