如何在没有错误的情况下提交任何内容? [英] How to git commit nothing without an error?
问题描述
我正在尝试编写一个结构脚本来执行 git commit
;但是,如果没有提交的内容,git将以 1
的状态退出。部署脚本将其视为不成功并退出。我确实希望检测到 提交失败的情况,所以我不能只为 git commit
失败提供结构忽略。我怎样才能允许空承诺失败被忽略,以便部署可以继续,但仍然捕获真正的提交失败时导致的错误?
def commit():
local(git add -p&&git commit)
git add -A
git diff-index --quiet HEAD || git commit -m'bla'
编辑:修正了 git diff根据Holger的评论,
命令
I'm trying to write a fabric script that does a git commit
; however, if there is nothing to commit, git exits with a status of 1
. The deploy script takes that as unsuccessful, and quits. I do want to detect actual failures-to-commit, so I can't just give fabric a blanket ignore for git commit
failures. How can I allow empty-commit failures to be ignored so that deploy can continue, but still catch errors caused when a real commit fails?
def commit():
local("git add -p && git commit")
Catch this condition beforehand by checking the exit code of git diff?
For example (in shell):
git add -A
git diff-index --quiet HEAD || git commit -m 'bla'
EDIT: Fixed git diff
command according to Holger's comment.
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