如何使用新的Gmail REST API成功发送消息? [英] How to send a message successfully using the new Gmail REST API?

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本文介绍了如何使用新的Gmail REST API成功发送消息?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我目前正在测试新的我发现,完整的消息需要在 raw 参数,请参阅示例:

 来自:John Doe< jdoe @ machine。例> 
致:Mary Smith< mary@example.net>
主题:说声Hello
日期:1997年11月21日星期五09:55:06 -0600
Message-ID:< 1234@local.machine.example>

这是一条消息,只是为了打招呼。所以,你好。

因此,在完成base64编码后,将它传递给 raw 参数而不使用任何其他参数,它工作正常。

编辑1:

正如@Amit提到的,它必须是 web安全的base64 编码,另请参阅 https://code.google.com/p/stringencoders/wiki/ WebSafeBase64


因此,要将base64 alpha转换为web安全格式,请按照以下步骤更改
建议:

  +  - > - (char 62,加上破折号)
/ - > _(char 63,斜线至下划线)
= - > *填充


仅转换 + - / _ 对我来说是足够的。



编辑2:

这里回答@Hjulle的问题:只需要 userId 并在请求正文中使用 raw 参数。假设您的电子邮件地址是 jdoe@machine.example



第一个Base64编码完整的信息(见上文)使用在线编码器,您将获得以下字符串:



'pre> RnJvbTogSm9obiBEb2UgPGpkb2VAbWFjaGluZS5leGFtcGxlPiAKVG86IE1hcnkgU21pdGggPG1h
cnlAZXhhbXBsZS5uZXQ + IApTdWJqZWN0OiBTYXlpbmcgSGVsbG8gCkRhdGU6IEZyaSwgMjEgTm92
IDE5OTcgMDk6NTU6MDYgLTA2MDAgCk1lc3NhZ2UtSUQ6IDwxMjM0QGxvY2FsLm1hY2hpbmUuZXhh
bXBsZT4KClRoaXMgaXMgYSBtZXNzYWdlIGp1c3QgdG8gc2F5IGhlbGxvLiBTbywgIkhlbGxvIi4 =

现在将 + 转换为 - / _ 并且您得到

  RnJvbTogSm9obiBEb2UgPGpkb2VAbWFjaGluZS5leGFtcGxlPiAKVG86IE1hcnkgU21pdGggPG1h 
cnlAZXhhbXBsZS5uZXQ-IApTdWJqZWN0OiBTYXlpbmcgSGVsbG8gCkRhdGU6IEZyaSwgMjEgTm92
IDE5OTcgMDk6NTU6MDYgLTA2MDAgCk1lc3NhZ2UtSUQ6IDwxMjM0QGxvY2FsLm1hY2hp bmUuZXhh
bXBsZT4KClRoaXMgaXMgYSBtZXNzYWdlIGp1c3QgdG8gc2F5IGhlbGxvLiBTbywgIkhlbGxvIi4 =

现在在 raw API Explorer的参数。


I'm currently trying to test the new Gmail REST API.

In the API Explorer it is possible to authorize requests using OAuth 2.0 and to execute a request, i.e. send a message.

First I authorized.

I'm using the following test data (and of course I used a valid to email address):

{    
   "raw": "c2VuZGluZyBhIG1haWwgdXNpbmcgR21haWwgUkVTVCBBUEk=",  
   "payload": { 
     "headers": [ 
       { "name": "to",      "value": "info@something.com"   }, 
       { "name": "from",    "value": "taifunbaer@gmail.com" }, 
       { "name": "subject", "value": "Test Gmail REST API"  } 
     ],
     "mimeType": "text/plain" 
   }
}

I also get a 200 OK and the following result back, which looks fine.

{
  "id": "146dee391881b35b",
  "threadId": "146dee391881b35b",
}

However, the mail will not be sent successfully and I can find an message from nobody@gmail.com in the inbox instead;: "An error occurred, your message has not been sent."

Questions:
1. Did someone test this successfully?
2. Do I have to add some other parameter to get this running?



EDIT: There are 2 different HTTP request methods,

  1. the Upload URI for media upload requests, and
  2. the Metadata URI for metadata-only requests

The API Explorer currently supports metadata requests only, which means plain-text messages without attachment, and this is what I'm trying to do.

解决方案

got it!

after reading the RFC 2822 specification I found out, that the complete message needs to be passed in the raw parameter, see the example:

From: John Doe <jdoe@machine.example> 
To: Mary Smith <mary@example.net> 
Subject: Saying Hello 
Date: Fri, 21 Nov 1997 09:55:06 -0600 
Message-ID: <1234@local.machine.example>

This is a message just to say hello. So, "Hello".

So after base64 encoding the complete message, passing it in the raw parameter without using any other parameter, it works fine.

Edit 1:
As @Amit mentioned, it must be web-safe base64 encoded, see also https://code.google.com/p/stringencoders/wiki/WebSafeBase64

So to convert the base64 alpha into a format that is "web-safe" the following changes are recommended:

+ --> - (char 62, plus to dash)
/ --> _ (char 63, slash to underscore)
= --> * padding

To only convert + to - and /to _ was sufficient for me.

Edit 2:
To answer the question of @Hjulle here an example: you only need the userId and in the request body the raw parameter. Let's assume, your email address is jdoe@machine.example

First Base64 encode the complete message (see above) using an online encoder and you get this string:

RnJvbTogSm9obiBEb2UgPGpkb2VAbWFjaGluZS5leGFtcGxlPiAKVG86IE1hcnkgU21pdGggPG1h
cnlAZXhhbXBsZS5uZXQ+IApTdWJqZWN0OiBTYXlpbmcgSGVsbG8gCkRhdGU6IEZyaSwgMjEgTm92
IDE5OTcgMDk6NTU6MDYgLTA2MDAgCk1lc3NhZ2UtSUQ6IDwxMjM0QGxvY2FsLm1hY2hpbmUuZXhh
bXBsZT4KClRoaXMgaXMgYSBtZXNzYWdlIGp1c3QgdG8gc2F5IGhlbGxvLiBTbywgIkhlbGxvIi4=

Now convert + to - and /to _ and you get

RnJvbTogSm9obiBEb2UgPGpkb2VAbWFjaGluZS5leGFtcGxlPiAKVG86IE1hcnkgU21pdGggPG1h
cnlAZXhhbXBsZS5uZXQ-IApTdWJqZWN0OiBTYXlpbmcgSGVsbG8gCkRhdGU6IEZyaSwgMjEgTm92
IDE5OTcgMDk6NTU6MDYgLTA2MDAgCk1lc3NhZ2UtSUQ6IDwxMjM0QGxvY2FsLm1hY2hpbmUuZXhh
bXBsZT4KClRoaXMgaXMgYSBtZXNzYWdlIGp1c3QgdG8gc2F5IGhlbGxvLiBTbywgIkhlbGxvIi4=

Now pass this in the raw parameter of the API Explorer.

这篇关于如何使用新的Gmail REST API成功发送消息?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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