使用谷歌脚本永久删除线程中的一条Gmail邮件 [英] permanently delete only one gmail message from a thread using a google script

问题描述

我想在垃圾桶中的线程中永久删除Gmail邮件。

我在那里合并了几个脚本，因此我可以延迟并跟踪电子邮件。它通过保存草稿起作用，然后脚本将草稿复制到新电子邮件中，在指定时间发送并将原稿发送到垃圾箱。问题是，有一段时间，垃圾邮件中的草稿会再次发送（我还没有弄清楚为什么）...

作为一种解决方法，我使用了以下最初发布的代码：永远删除电子邮件1 ：

  function cleanUp（）{
 var threads = GmailApp.search（in：trash is：draft）; 
 Logger.log（threads.length）; 
 for（var i = 0; i< threads.length; i ++）{
 Logger.log（threads [i] .getId（））; 
 Gmail.Users.Message.remove（'me'，threads [i] .getId（））; 
} 
} 
  

这很好，直到前一阵子。如果草稿在多条消息中的线程中，只有草稿被删除了......我现在在第6行出现了一个错误：无法调用方法删除undefined。

在这篇文章中：永久删除电子邮件2 ，建议用

 替换第6行Gmail.Users.Threads.remove（'me' ，线程[I] .getId（））; 
  

这种情况不会出现任何错误，但如果草稿位于具有多条消息的线程中，整个线程被删除，而不仅仅是草稿...

那么，有没有办法让只删除草稿？

我试着在线程中调用草稿的消息ID并使用原始行6：

 函数cleanUp2（）{
 var threads = GmailApp.search（in：trash is：draft）; 
 Logger.log（threads.length）; 
 for（var i = 0; i< threads.length; i ++）{
 var messages = threads [i] .getMessages（）; 
 Logger.log（messages.length）; 
 for（var j = 0; j  if（messages [j] .isDraft（））{
 Logger.log（'id msg：' +消息[j] .getId（））; 
 Gmail.Users.Message.remove（'me'，messages [j] .getId（））; 
} 
} 
} 
} 
  

但我得到了同样的错误，现在在线10 ...

我也试过使用这个函数：

 function deleteMessage（userId，messageId）{
 var request = gapi.client.gmail.users.messages.delete（{$ b $'userId'：userId，
'id'：messageId 
}）; 
 request.execute（
 function（resp）{}）; 
} 
  

你可以在google的开发者页面找到：这里。在尝试这个API部分它的工作原理，但在我的实施中，我得到了第2行的错误，说（从西班牙语翻译，所以我不知道它是否确切）：名称（？） （后？）运算符。如果我复制功能在一个单独的选项卡中，我可以保存它，并显示相同的错误...

任何帮助将不胜感激...

问候，

解决方案

通过http请求：

  function cleanUp2（）{
 var threads = GmailApp.search（in：垃圾是：草稿）; 
 Logger.log（threads.length）; 
 
 var userId ='[e-mail]'; 
 var options = {
'method'：'delete'，
'muteHttpExceptions'：true 
}; 
 
 for（var i = 0; i< threads.length; i ++）{
 var messages = threads [i] .getMessages（）; 
 Logger.log（messages.length）; （var j = 0; j  if（messages [j] .isDraft（））{
 Logger.log（'b 
 $ b' id msg：'+ messages [j] .getId（））; 
 var url ='https://www.googleapis.com/gmail/v1/users/'+ userId +'/ messages /'+ messages [j] .getId（）; 
 var response = UrlFetchApp.fetch（url，options）; 
 Logger.log（response）; 
} 
} 
} 
} 
  

I want to permanently delete a Gmail message inside a thread already in the trash.

I merged a few scripts around there, so I can delay and track emails. It works by saving a draft, then the script copy the draft into a new email, send it at the specified time and send the original draft to trash. The problem is that once in a while, the drafts that are in the trash are sent again (i haven't been able to figure out why yet)...

As a workaround, I was using the following code that that was originally posted here: delete forever emails 1:

function cleanUp() {
  var threads = GmailApp.search("in:trash is:draft");
  Logger.log(threads.length);
  for (var i = 0; i < threads.length; i++) {
    Logger.log(threads[i].getId());
    Gmail.Users.Message.remove('me',threads[i].getId());
  }
}

This was working fine, until a while ago. If the draft was inside a thread with more than 1 message, only the draft was deleted... I got now an error on line 6 that says: "Cannot call method "remove" of undefined".

In this post: delete forever emails 2, it is suggested to replace line 6 by

Gmail.Users.Threads.remove('me',threads[i].getId());

This dosn't get any errors, but if the draft is in a thread with more than one message, the whole thread is deleted instead of only the draft...

So, is there a way to get only the draft erased?

I tried calling the message id of the draft inside the thread and use the original line 6:

function cleanUp2() {
  var threads = GmailApp.search("in:trash is:draft");
  Logger.log(threads.length);      
  for (var i = 0; i < threads.length; i++) {
    var messages = threads[i].getMessages();
    Logger.log(messages.length);        
    for (var j = 0; j < messages.length; j++){
      if (messages[j].isDraft()){
        Logger.log('id msg: ' + messages[j].getId());
        Gmail.Users.Message.remove('me',messages[j].getId());        
      }    
    }
  }
}

But I got the same error, now on line 10...

I also tried using this function:

function deleteMessage(userId, messageId) {
  var request = gapi.client.gmail.users.messages.delete({
    'userId': userId,
    'id': messageId
  });
  request.execute(
    function(resp) { });
}

That you can find in the developers page of google: here. In the "try this API" section it works, but in my implementation i got an error on line 2 that says (translated from Spanish so i don't know if it will be exact): "a name (?) is missing behind (after?) operator "."" And if i copy the function in a separated tab, i can save it and the same error is showed...

Any help will be appreciated...

Regards,

解决方案

i finally made it trough an http request:

function cleanUp2() {
  var threads = GmailApp.search("in:trash is:draft");
  Logger.log(threads.length);

  var userId = '[e-mail]';
  var options = {
   'method' : 'delete',
   'muteHttpExceptions': true
 };

  for (var i = 0; i < threads.length; i++) {
    var messages = threads[i].getMessages();
    Logger.log(messages.length);

    for (var j = 0; j < messages.length; j++){
      if (messages[j].isDraft()){
        Logger.log('id msg: ' + messages[j].getId());
        var url = 'https://www.googleapis.com/gmail/v1/users/' + userId + '/messages/' + messages[j].getId();
        var response = UrlFetchApp.fetch(url,options);
        Logger.log(response);            
      }    
    }
  }
}

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