Android的：先从参数服务 [英] Android: start service with parameter

问题描述

要从Activiy我用 startService（MyService.class）开始我服务。这个伟大的工程，但在特殊情况下，服务应该以不同的开始。我想一些参数传递给服务启动。

To start my service from an Activiy I use startService(MyService.class). This works great, but in a special case the service should be started differently. I want to pass some parameters to the service start.

我想在我的活动如下：

Intent startMyService= new Intent();
startMyService.setClass(this,LocalService.class);
startMyService.setAction("controller");
startMyService.putExtra(Constants.START_SERVICE_CASE2, true);

startService(startMyService);

在我的服务我使用：

public class MyIntentReceiver extends BroadcastReceiver {

@Override
public void onReceive(Context context, Intent intent) {

        if (intent.getAction().equals("controller")) 
        {
                // Intent was received                               
        }

    }
} 

在IntentReceiver注册在的onCreate（）是这样的：

The IntentReceiver is registered in onCreate() like this:

IntentFilter mControllerIntent = new IntentFilter("controller");
MyIntentReceiver mIntentReceiver= new MyIntentReceiver();
registerReceiver(mIntentReceiver, mControllerIntent);

通过此解决方案的服务启动，但意图不是接收。 我如何开始一个服务，并通过我的参数？

With this solution the service starts but the intent is not received. How can I start a Service and pass my parameters?

感谢您的帮助！

推荐答案

步骤＃1：删除你的的BroadcastReceiver 实施

Step #1: Delete your BroadcastReceiver implementation.

第2步：检查意图您服务获取 onStartCommand（）通过，并期待在动作的getAction（）。

Step #2: Examine the Intent your service gets in onStartCommand() and look at the action via getAction().

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