如何乘以整数的持续时间? [英] How to multiply duration by integer?

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问题描述

为了测试并发的goroutines,我在函数中添加了一行,以使它随机返回一个时间(最多一秒)

To test concurrent goroutines, I added a line to a function to make it take a random time to return (up to one second)

time.Sleep(rand.Int31n(1000) * time.Millisecond)

然而,当我编译了,我得到了这个错误:

However when I compiled, I got this error


.\crawler.go:49:无效操作:rand.Int31n(1000)* time。毫秒(不匹配类型int32和time.Duration)

.\crawler.go:49: invalid operation: rand.Int31n(1000) * time.Millisecond (mismatched types int32 and time.Duration)

任何想法?我怎么能乘以一个持续时间?

Any ideas? How can I multiply a duration?

推荐答案

int32 and time.Duration 是不同的类型。您需要将 int32 转换为 time.Duration ,例如 time.Sleep( time.Duration(rand.Int31n(1000))* time.Millisecond)

int32 and time.Duration are different types. You need to convert the int32 to a time.Duration, such as time.Sleep(time.Duration(rand.Int31n(1000)) * time.Millisecond).

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