如何通过它的值对Map [string] int进行排序? [英] How to sort a Map[string]int by its values?
本文介绍了如何通过它的值对Map [string] int进行排序?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
给出这个代码块
$ $ p $ $ $ c $ map map [string] int {hello:10,foo:20, bar:20}
我想打印出来
foo,20
bar,20
hello,10
按照从高到低的顺序排列
谢谢!
解决方案
通过Andrew Gerrand找到Golang-nuts的答案可以通过编写len / less / swap函数来实现排序接口 / p>
func rankByWordCount(wordFrequencies map [string] int)PairList {
pl:= make(PairList,len(wordFrequencies) )
i:= 0
for k,v:=范围wordFrequencies {
pl [i] = Pair {k,v}
i ++
}
sort.Sort(sort.Reverse(pl))
返回pl
}
类型对结构{
键字符串
值int
}
类型PairList [] Pair
func(p PairList)Len()int {return len(p)}
func(p PairLis t)Less(i,j int)bool {return p [i] .Value< (p,j)= p [j],p [i]}
code>
对于原文,请在此处找到 https://groups.google.com/forum/#!topic/golang-nuts/FT7cjmcL7gw
Given this code block
map[string]int {"hello":10, "foo":20, "bar":20}
I would like to print out
foo, 20
bar, 20
hello, 10
In the order of highest to lowest
Thanks!
解决方案
Found the answer on Golang-nuts by Andrew Gerrand
You can implement the sort interface by writing the len/less/swap functions
func rankByWordCount(wordFrequencies map[string]int) PairList{
pl := make(PairList, len(wordFrequencies))
i := 0
for k, v := range wordFrequencies {
pl[i] = Pair{k, v}
i++
}
sort.Sort(sort.Reverse(pl))
return pl
}
type Pair struct {
Key string
Value int
}
type PairList []Pair
func (p PairList) Len() int { return len(p) }
func (p PairList) Less(i, j int) bool { return p[i].Value < p[j].Value }
func (p PairList) Swap(i, j int){ p[i], p[j] = p[j], p[i] }
For the original post, please find it here https://groups.google.com/forum/#!topic/golang-nuts/FT7cjmcL7gw
这篇关于如何通过它的值对Map [string] int进行排序?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
查看全文