重写正则表达式而不是否定 [英] Rewrite regex without negation

问题描述

$ b

https：：\ / \ /（（）由于我使用的是golang / regexp lib，因此我们可以使用golang / regexp lib，我无法使用它，因为我的否定（？！..

我想要什么要处理它，就是选择所有从http / https最后一次出现的文本直到结束。

  sometextsometexhttp：/ /websites.com/path/subpath/#query1sometexthttp://websites.com/path/subpath/#query2 
  

=>输出： http://websites.com/path/subpath/#query2

任何人都可以帮助我解决问题，我花了好几个小时尝试不同的方式来重现相同的结果，但没有成功。

  https：
 
 ：] * $ 
  

Regex住在这里。

I have wrote this regex to help me extract some links from some text files:

https?:\/\/(?:.(?!https?:\/\/))+$

Because I am using golang/regexp lib, I'm not able to use it, due to my negation (?!..

What I would like to do with it, is to select all the text from the last occurance of http/https till the end.

sometextsometexhttp://websites.com/path/subpath/#query1sometexthttp://websites.com/path/subpath/#query2

=> Output: http://websites.com/path/subpath/#query2

Can anyone help me with a solution, I've spent several hours trying different ways of reproducing the same result with no success.

解决方案

Try this regex:

https?:[^:]*$

Regex live here.

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