如何在Go中获得十六进制编码的md5哈希 [英] How to get hex-encoded md5 hash in Go

问题描述

  running_hash：= md5。我试图在Go中获取文件的md5哈希值。新（）; //输入hash.Hash 
 running_hash.Write（data）; // data is [] byte 
 sum：= running_hash.Sum（）; // [] uint8根据编译器
  

但是当我试图获取散列的字符串'总和'（ http://golang.org/pkg/hash/ ），通过

  sumstring：= string（sum）; //返回'Ӿ  ]앿  N  '或类似的
  

应该是 d3be9e835dec95bfbef34ebe1fbf03da 。当我尝试以字节为单位进行转换时，我得到了相同的废话，只有不同的字符。

我如何获得散列的字符串？

解决方案

基本上，你已经得到了二进制数据，但它看起来像你期待的十六进制。查看转换例程的十六进制包，特别是 EncodeToString 。我不是一个Go程序员，但我认为如果你只是将 sum 传递给 hex.EncodeToString ，你会得到您预期的答案。

I'm trying to get the md5 hash of a file in Go, like thus:

running_hash := md5.New(); // type hash.Hash
running_hash.Write(data);  // data is []byte
sum := running_hash.Sum(); // []uint8 according to the compiler

But when I try to get the string of the hash's 'sum' (http://golang.org/pkg/hash/), via

sumstring := string(sum);  // returns 'Ӿ��]앿��N��' or similar

when the hash is supposed to be d3be9e835dec95bfbef34ebe1fbf03da. I get the same sort of nonsense, only with different characters, when I try to convert on a byte-by-byte basis.

How am I meant to get the hash's string?

解决方案

Basically, you've got the binary data but it looks like you're expecting hex. Have a look at the hex package for conversion routines, especially EncodeToString. I'm not a Go programmer, but I think if you just pass sum into hex.EncodeToString, you'll get the answer you expected.

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