如果不发送新行,如何读取由服务器发送的数据(xml) [英] How to read data (xml) sent by server if it doesn't send new line
问题描述
conn,err:= net.Dial(tcp,s.Addr +:5222)
// ...
r:= bufio.NewReader(conn)
// ...
s,err:= sRReadString(10)//读取字符串
但是有一个问题,服务器不会发送\ 10(换行符)符号。我也试过12但没有任何运气。 readLine函数也是如此,因为它也依赖于\ 10。那么如何读取服务器发送的数据呢?
我尝试使用'>'作为分隔符并成功接收部分消息(可预测)。我有一个想法循环,而错误是零,并使用'>'的分隔符,但它也没有工作。
我的研究表明,消息的最后一个符号实际上是'>'(62),并且末尾没有其他任何东西。
使用 xml.Decoder 从XMPP流中读取节。
conn,err:= net.Dial(tcp,s.Addr +:5222)
if err!= nil {
//处理错误
}
dec:= xml.NewDecoder(conn)
使用解码器 Token 方法读取根目录文档元素并跳过节之间的字符数据:
func readStartElement(dec * xml.Decoder)(xml.StartElement,error ){
for {
t,err:= dec.Token()
if err!= nil {
return xml.StartElement {},err
}
switch t:= t。(type){
case xml.StartElement:
return t,nil
}
}
}
code>
使用解码器
方法来读取节:呃ror){ func readStanza(dec * xml.Decoder)(interface {nofollow}> DecodeElement
se,err:= readStartElement(dec)
if err!= nil {
return nil,err
}
var v interface {}
switch se.Name.Space ++ se.Name.Local {
casejabber:client message:
v =& jabberMessage {} // jabberMessage是由app定义的结构类型消息
//在这里添加其他节类型。
默认值:
v =& struct {} {}
}
if err:= dec.DeocdeElement(v,& se); err!= nil {
return nil,err
}
return v,nil
}
在readStanza的返回值上键入开关以处理不同类型的收到节。
客户端同步读取节。
conn,err:= net.Dial(tcp,s.Addr + :5222)
if err!= nil {
//处理错误
}
dec:= xml.NewDecoder(conn)
/ /读取并放弃根元素
_,err:= readStartElement(dec)
if err!= nil {
//处理错误
}
//读取经节
用于{
v,err:= readStanza(dec)
if err!= nil {
//处理错误
// //必须跳出循环出错
}
switch v:= v。(类型){
case * jabberMessage:
//句柄消息
case * someOtherStanzaType:
//处理其他节类型
// ...等等
}
}
Let's say we try to communicate with a server (XMPP) which sends back XML data. We can use
conn, err := net.Dial("tcp", s.Addr+":5222")
//...
r := bufio.NewReader(conn)
//...
s, err := s.R.ReadString(10) // to read a string
But there is one problem that the server doesn't send the \10 (newline) symbol. I also tried 12 but without any luck. Same goes for readLine function as it also relies on \10. So how do I read the data sent by server? I tried using '>' as a delimiter and succeeded to receive only parts of the messages (predictable). I had an idea to loop while error is nil and use delimiter of '>' but it also didn't work. My research shown that the last symbol of the message is really '>' (62) and there is not any anything else at the end.
Use an xml.Decoder to read stanzas from an XMPP stream.
conn, err := net.Dial("tcp", s.Addr+":5222")
if err != nil {
// handle error
}
dec := xml.NewDecoder(conn)
Use the decoder Token method to read the root document element and to skip over character data between stanzas:
func readStartElement(dec *xml.Decoder) (xml.StartElement, error) {
for {
t, err := dec.Token()
if err != nil {
return xml.StartElement{}, err
}
switch t := t.(type) {
case xml.StartElement:
return t, nil
}
}
}
Use the decoder DecodeElement method to read a stanza:
func readStanza(dec *xml.Decoder) (interface{}, error) {
se, err := readStartElement(dec)
if err != nil {
return nil, err
}
var v interface{}
switch se.Name.Space + " " + se.Name.Local {
case "jabber:client message":
v = &jabberMessage{} // jabberMessage is struct type defined by app for messages
// Add other stanza types here.
default:
v = &struct{}{}
}
if err := dec.DeocdeElement(v, &se); err != nil {
return nil, err
}
return v, nil
}
Type switch on the return value from readStanza to handle the different types of received stanzas.
A client reads stanzas synchronously. Here's rough outline (ignoring authentication, etc).
conn, err := net.Dial("tcp", s.Addr+":5222")
if err != nil {
// handle error
}
dec := xml.NewDecoder(conn)
// read and discard root element
_, err := readStartElement(dec)
if err != nil {
// handle error
}
// read stanzas
for {
v, err := readStanza(dec)
if err != nil {
// handle error
// must break out of loop on error
}
switch v := v.(type) {
case *jabberMessage:
// handle message
case *someOtherStanzaType:
// handle other stanza types
// ... and so on
}
}
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