带有GO的Visual Studio代码 - 多个主要声明（启动设置） [英] Visual Studio Code with GO - Multiple main declarations (launch settings)

问题描述

我是VS代码和Golang的新手。

我有一个包含两种不同服务的现有项目 - 让我们叫一个A和第二个B.

A和B位于同一目录下。

每当我尝试运行A或B时，出现以下错误：

 ＃目录/目录/目录/ A& B_Directory 
 ./A.go:12:6：在此块中重新声明
之前在./B处声明.go：18：6 
  

我试着玩 launch.json 文件，添加以下部分：

  {
name：Launch Program ，
type：go，
request：launch，
mode：debug，
program：FullDirectory / A。去

  

在程序属性中尝试设置为 $ {file} 以及许多其他变体失败。

我喜欢某个方向，我有点迷路。
Thanks。

解决方案

： / strong>，我同意其他人的看法，您应将 service A和B分隔到不同的目录中。

回答您的问题：要启动特定文件，请使用以下配置来模拟 go run current-file ：

  {
version：0.2.0，
configurations：[
 {
name：运行当前文件，
type：go，
request：launch，
mode： exec，
program：full-path-to-go.exe，
args：[run，$ {file}]，
 showLog：true 
} 
] 
} 
  

模式 exec 用于启动属性程序中给出的预构建二进制文件（您必须指定完整路径为 go 二进制）。然后作为参数，将 run 和filename（ $ {file} ）添加到属性 ARGS 。

I'm new to VS code and Golang.
I have an existing project containing 2 different services - let's call one A and the second one B.
Both A and B sits under the same directory.

Whenever I try to run A or B, I get the following error :

# directory/directory/directory/A&B_Directory
./A.go:12:6: main redeclared in this block
    previous declaration at ./B.go:18:6

I tried playing with the launch.json file, adding the following sections :

   {
        "name": "Launch Program",
        "type": "go",
        "request": "launch",
        "mode": "debug",
        "program": "FullDirectory/A.go"
    }

Also tried in the program attribute to set to ${file} and many other variations that failed.

I'd love for some direction, I'm kinda lost. Thanks.

解决方案

Disclaimer: this is not the recommended approach, I'm agree with others, you shall separate the service A and B into different directory.

Answer to your question: To launch a specific file, use the following configuration to emulate go run current-file:

{
    "version": "0.2.0",
    "configurations": [
        {
            "name": "Run current file",
            "type": "go",
            "request": "launch",
            "mode": "exec",
            "program": "full-path-to-go.exe",
            "args": ["run", "${file}"],
            "showLog": true
        }
    ]
}

Mode exec is for launching pre-built binary given in the property program (you must specify full path to go binary). Then as the arguments, just add run and filename (${file}) to property args.

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