如何在python AppEngine中构建请求时获取url？ [英] How to fetch a url while building a request in python AppEngine?

问题描述

为了能够在某人点击我的服务的 / show_data / url时构建获取响应，而在构建它时，我想要获取url / retrieve_data / 来自同一个服务。我怎样才能在另一个线程中启动它，这样我就可以避免我收到的DeadLineExceeded错误？我使用的是Python 2.7， threadsafe = true 。

In order to be able to build a get response when somebody hits /show_data/ url of my service, while I am building it I want to fetch the url /retrieve_data/ from the same service. How can I fire it up in a different thread so I can avoid the DeadLineExceeded errors I am receiving? I am using python 2.7, with threadsafe=true.

所以我对<$ c
$ b

so I have something like this for the /show_data/ handler:

def get(self):
  url = '/retrieve_data/'
  data_from_my_service = urlfetch.fetch(url)
  do_something_with_data(data_from_my_service)
  self.redirect('/')

推荐答案

您应该使用 urlfetch异步API （无需涉及线程）。

You should use urlfetch async API (no need to involve threads).

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