如何将嵌套平铺转换为标准SQL [英] How to convert a nested flatten into Standard SQL
问题描述
选择* FROM FLATTEN(FLATTEN([DB.table1],record.atr))记录。 atr.value)
WHERE record.atr.value IN1
我明白了< hQuery =https://chartio.com/resources/tutorials/how-to-flatten-data-using-google-bigquerys-legacy-vs-standard-sql/ =nofollow noreferrer> BigQuery现在自动变平,所以我认为这会做到这一点:
SELECT * FROM`DB.table1`
WHERE record.atr.value IN1
然而,我得到一个错误错误:Can not在类型ARRAY,sv ARRAY,... >> at [2:17]上访问字段值
如何将其转换为标准SQL查询? 在使用标准SQL时,BigQuery不会自动将数组展平; 您提供的链接表明相反。在你的情况下,查询将是这样的:
#standardSQL
SELECT * EXCEPT(value),value
FROM`Db.table1`
CROSS JOIN UNNEST(record.atr)AS atr
CROSS JOIN UNNEST(atr.value)AS值;
如果您想为空数组获得一行,可以使用 LEFT JOIN
改为:
#standardSQL
SELECT * EXCEPT(value),value
FROM`Db.table1`
LEFT JOIN UNNEST(record.atr)AS atr
LEFT JOIN UNNEST(atr.value)AS值;
以下是您可以尝试运行的示例查询:
#standardSQL
WITH AS(
SELECT STRUCT(ARRAY< STRUCT< x STRING,value ARRAY< INT64>>> [(' ('bar',[3,4,5])] AS atr)AS记录UNION ALL
SELECT STRUCT(ARRAY< STRUCT< x STRING,value ARRAY< INT64> >>> [('baz',[6,7])])
)
SELECT * EXCEPT(value)
FROM输入
CROSS JOIN UNNEST(record.atr )AS atr
CROSS JOIN UNNEST(atr.value)AS值;
Currently using BigQuery From google. My legacy query looks like:
Select * FROM FLATTEN(FLATTEN([DB.table1], record.atr), record.atr.value)
WHERE record.atr.value IN "1"
I understand BigQuery now automatically flattens tables so i thought this would do the trick:
SELECT * FROM `DB.table1`
WHERE record.atr.value IN "1"
However i get an error Error: Cannot access field value on a value with type ARRAY, sv ARRAY, ...>> at [2:17]
How can i convert this to Standard SQL query?
BigQuery does not automatically flatten arrays when using standard SQL; the link that you provided indicates the opposite. In your case, the query would be something like this:
#standardSQL
SELECT * EXCEPT(value), value
FROM `Db.table1`
CROSS JOIN UNNEST(record.atr) AS atr
CROSS JOIN UNNEST(atr.value) AS value;
If you want to get a row even for empty arrays, you can use LEFT JOIN
instead:
#standardSQL
SELECT * EXCEPT(value), value
FROM `Db.table1`
LEFT JOIN UNNEST(record.atr) AS atr
LEFT JOIN UNNEST(atr.value) AS value;
Here is a sample query that you can try running:
#standardSQL
WITH Input AS (
SELECT STRUCT(ARRAY<STRUCT<x STRING, value ARRAY<INT64>>>[('foo', [1, 2]), ('bar', [3, 4, 5])] AS atr) AS record UNION ALL
SELECT STRUCT(ARRAY<STRUCT<x STRING, value ARRAY<INT64>>>[('baz', [6, 7])])
)
SELECT * EXCEPT (value)
FROM Input
CROSS JOIN UNNEST(record.atr) AS atr
CROSS JOIN UNNEST(atr.value) AS value;
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