如何在bigquery中查找重复结构中的最后一个项目 [英] How to find last item in a repeated structure in bigquery
问题描述
SELECT
记录中的第一个(cell.value),
LAST(cell.value)记录
FROM [publicdata:samples.trigrams]
其中ngram =!!那个
<2>)或者如果您想要更高级的内容,可以使用 POSITION
POSITION(field)
- 返回基于one,在一组重复字段中的字段的顺序位置。
您可以从trigrams中检查样本(点击Details以查看未展开的模式)
https://bigquery.cloud.google.com/table/publicdata:samples.trigrams?pli=1
当你运行POSITION时,你会得到顺序该领域。
SELECT
ngram,
cell.value,
position(cell.volume_count)as pos,
FROM [publicdata:samples.trigrams]
where ngram =!!那个
现在您已经拥有该位置,您可以查询最后一个。
I have a nested repeated structure, the repeated structure is of variable length. For example, it could be a person object with a repeated structure that holds cities the person has lived in. I'd like to find the last item in that list say to find current city person lives in. Is there an easy way to do this, I tried looking around jsonpath functions but I'm not sure how to use it with "within". Any help please?
1) You can use LAST and WITHIN
SELECT
FIRST(cell.value) within record ,
LAST(cell.value) within record
FROM [publicdata:samples.trigrams]
where ngram = "! ! That"
2) or if you want something more advanced you can use POSITION
POSITION(field)
- Returns the one-based, sequential position of field within a set of repeated fields.
You can check the samples from trigrams (click on Details to see the unflatten schema) https://bigquery.cloud.google.com/table/publicdata:samples.trigrams?pli=1
And when you run POSITION, you get the ordering of that field.
SELECT
ngram,
cell.value,
position(cell.volume_count) as pos,
FROM [publicdata:samples.trigrams]
where ngram = "! ! That"
Now that you have the position, you can query for last one.
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