在Chrome扩展程序的上下文菜单中弹出窗口 [英] popup window at chrome extensions' context menu

问题描述

我正在开发Chrome扩展并遇到问题。我已经添加了一个项目到chrome的上下文菜单，并且想要在菜单项被点击时打开一个弹出窗口。我的代码如下所示：

I'm developing a chrome extension and have a problem. I've added an item to chrome's context menu and want to open a popup window if the menu item is clicked. My code looks like this:

function popup(url) {
window.open(url, "window", "width=600,height=400,status=yes,scrollbars=yes,resizable=yes");
}

chrome.contextMenus.create({"title": "Tumblr", "contexts":["page","selection","link","editable","image","video","audio"], "onclick": popup('http://example.com')});

但是这段代码不能按我的要求工作。点击上下文项目后，弹出窗口不会出现，而是在Chrome扩展程序首选项中刷新扩展名后。

But this code doesn't work as I want. The popup window doesn't appear after an click on the context item, but rather after a refresh of the extension in the chrome extension preferences.

预先感谢！

推荐答案

chrome.contextMenus.create({... "onclick": popup('http://example.com')})

调用弹出窗口立即生效，导致弹出窗口被打开。你必须传递一个函数的引用。为了让你的代码工作，将函数调用包装在一个函数中：



invokes the popup function immediately, causing a pop-up to be opened. You have to pass a reference to a function. To get your code to work, wrap the function call in a function:

chrome.contextMenus.create({
    "title": "Tumblr",
    "contexts": ["page", "selection", "link", "editable", "image", "video", "audio"],
    "onclick": function() {
        popup('http://example.com');
    }
});

window.open（）创建一个弹出窗口。另一种方法（只是为了让您知道它存在）是 chrome.windows.create 。

window.open() can be used to create a popup. An alternative method (just to let you know that it exists) is chrome.windows.create.

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