Google地图 - 获取区域/邻域的多边形边界 [英] Google Maps - Get Polygon border of zones/neighborhood

问题描述

我想在Google Maps API v3上进行一次简单的搜索，然后获得带有彩色多边形的地图，如下图所示：

搜索：pinheiros，圣保罗

解决方案

我通过使用

• 点击右边的邻居按钮，然后选择编辑多元。
  将JSON转换为WKT。我不复制整个JSON仅Regex中的points数组中的对象。在RegExr上，我复制替换的文本并粘贴到 POLYGON（（pastehere））中。
  
  
  

  重要！应用正则表达式后，您需要重复上一点的第一个点。

  
  
  'BLOCKQUOTE>
  

  <强> -61.956523060798645 -10.877613428213532 下， - 61.95640504360199 -10.877718788854143，-61.956791281700134 -10.878393096072424，-61.95735991001129 -10.87805594265392，-61.95682346820831 -10.877339490373695，的 -61.956523060798645 -10.877613428213532

  
  

  然后你得到这样的东西：

    POLYGON（（ -  61.956523060798645 -10.877613428213532，-61.95640504360199 -10.877718788854143，-61.956791281700134 -10.878393096072424，-61.95735991001129 -10.87805594265392，-61.95682346820831 -10.877339490373695，-61.956523060798645 -10.877613428213532））
    
   
  可以插入支持WKT的数据库（如MySQL）。
   
   
   
   WikiMapia有一个 API ，那么所有这些过程都可以是au tomatic，但这对我来说很好。
   
  I want to make a simple search on Google Maps API v3 and get as a result the map with a colored polygon like the picture below:
  
  Search: pinheiros, sao paulo
  
  解决方案
  I got it by using WikiMapia data.
  
  The steps are:
  
  
  Open WikiMapia.
  Press F12 or Ctrl+Shift+I.
  
  
  
  
  
  Search the location that you want.
  Click with the right button on neighborhood and choose Edit Poly.
  
  On the developer tools click in Network and filter by getPolygon.
  
  Copy server response that looks like:
  
  And go to Console tab to execute the function: Wikimapia.Parser.Itiles.prototype.decodePolygon("Copyed text here");
  Press enter to execute after this the Console will return the object with the points (The path of Poly).
  
  
  I use JSON.stringify to transform the object in JSON.
  
  Example:
  JSON.stringify(Wikimapia.Parser.Itiles.prototype.decodePolygon("-619402099;-109032887;02fe8953fffe5a000ae5fe379a000fedffd250000e40ffd6050007f7ffeff2001925ffd59b001f6fffdc310012dcffed10003b82ffd9b9005514ffc4520053d2ffc807000c92fff82dfffde7000e670005070012ef0009390021bf000572001358fffc3a001a57fffa210013c1ffff940036530008610022fc000284004732fff5f0001fb1fff2960013c1fff80800594efffde7002c72000f16004b5000204600416f0013b2002292"))
  The code above will return this JSON (indentation in JsonFormatter):
  {
     "points":[
        {
           "lat":-10.9032887,
           "lng":-61.9402099
        },
        {
           "lat":-10.9032466,
           "lng":-61.9306183
        },
        {
           "lat":-10.8915629,
           "lng":-61.9308972
        },
        {
           "lat":-10.8903934,
           "lng":-61.9313049
        },
        {
           "lat":-10.8893188,
           "lng":-61.9316697
        },
        {
           "lat":-10.8889079,
           "lng":-61.9318736
        },
        {
           "lat":-10.8878227,
           "lng":-61.9325173
        },
        {
           "lat":-10.8869061,
           "lng":-61.933322
        },
        {
           "lat":-10.8864214,
           "lng":-61.9338048
        },
        {
           "lat":-10.8854416,
           "lng":-61.9353282
        },
        {
           "lat":-10.8839139,
           "lng":-61.9375062
        },
        {
           "lat":-10.8824811,
           "lng":-61.939652
        },
        {
           "lat":-10.8822809,
           "lng":-61.9399738
        },
        {
           "lat":-10.8826496,
           "lng":-61.9399202
        },
        {
           "lat":-10.8831343,
           "lng":-61.9400489
        },
        {
           "lat":-10.8839982,
           "lng":-61.940285
        },
        {
           "lat":-10.8844934,
           "lng":-61.9404244
        },
        {
           "lat":-10.8851677,
           "lng":-61.9403279
        },
        {
           "lat":-10.8856734,
           "lng":-61.9401777
        },
        {
           "lat":-10.8870641,
           "lng":-61.940167
        },
        {
           "lat":-10.8879597,
           "lng":-61.9403815
        },
        {
           "lat":-10.8897823,
           "lng":-61.9404459
        },
        {
           "lat":-10.8905936,
           "lng":-61.9401884
        },
        {
           "lat":-10.8910993,
           "lng":-61.9398451
        },
        {
           "lat":-10.8933855,
           "lng":-61.9396412
        },
        {
           "lat":-10.8945233,
           "lng":-61.9395876
        },
        {
           "lat":-10.8964513,
           "lng":-61.9399738
        },
        {
           "lat":-10.8981264,
           "lng":-61.9408
        },
        {
           "lat":-10.8990114,
           "lng":-61.9413042
        }
     ],
     "bounds":{
        "left":-61.9413042,
        "bottom":-10.9032887,
        "right":-61.9306183,
        "top":-10.8822809,
        "centerLatLng":null
     }
  }
  Finally I use regex like this regexr.com/3c5m2 to turn JSON into WKT. I don't copy entire JSON only the objects in "points" array in Regex. On RegExr I copy the replaced text and paste in POLYGON((pastehere)). 
  
  Important! After apply the regex you need to repeat the first point in last point.
  
    
  -61.956523060798645 -10.877613428213532,-61.95640504360199 -10.877718788854143,-61.956791281700134 -10.878393096072424,-61.95735991001129 -10.87805594265392,-61.95682346820831 -10.877339490373695,-61.956523060798645 -10.877613428213532
  Then you get something like this:
  POLYGON((-61.956523060798645 -10.877613428213532,-61.95640504360199 -10.877718788854143,-61.956791281700134 -10.878393096072424,-61.95735991001129 -10.87805594265392,-61.95682346820831 -10.877339490373695,-61.956523060798645 -10.877613428213532))
  That can be inserted in database that supports WKT (like MySQL).
  
  WikiMapia has an API then all of this process can be automatic, but this works fine for me.
  
                          
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