如何在谷歌地图上获得两点（火车站）的纬度/经度？ [英] How can I get Lat/Lng of two points (train station) on google maps?

问题描述

我即将追踪与两个站之间的铁路的方向服务。
问题是我无法得到两个站的纬度/经度，它总是得到一个邻居点。

路线是（在google上搜索地图网站）：

  Ceres，TO到Stazione Porta Nuova，Corso Vittorio Emanuele II，58，Torino 
 
 code> 

我需要Ceres（火车站）和Stazione Porta Nuova的Lat / Lng，Corso Vittorio Emanuele II，58，都灵（火车站）。如何获得它们？

因此，我可以在我的地图中绘制相同的铁路线（棕线）。


解决方案

  public class GetXMLTask 
 {
 static double longitute; 
静态双纬度; 
 public JSONObject getLocationInfo（String address）
 {
 StringBuilder stringBuilder = new StringBuilder（）; 
尝试
 {
 address = address.replaceAll（，％20）; 
 HttpPost httppost = new HttpPost（http://maps.google.com/maps/api/geocode/json?address=+ address +& sensor = false）; 
 HttpClient client = new DefaultHttpClient（）; 
 HttpResponse响应; 
 stringBuilder = new StringBuilder（）; 
 response = client.execute（httppost）; 
 HttpEntity entity = response.getEntity（）; 
 InputStream stream = entity.getContent（）; 
 int b; （（b = stream.read（））！= -1）
 
（
）stringBuilder.append（（char）b）; 
 
 $ b $ catch（ClientProtocolException e）
 {
 Log.i（getLocationInfo ClientProtocolException，e.toString（））; 
 
 catch（IOException e）
 {
 Log.i（getLocationInfo IOException，e.toString（））; 
} 
 JSONObject jsonObject = new JSONObject（）; 
尝试
 {
 jsonObject = new JSONObject（stringBuilder.toString（））; 
 
 catch（JSONException e）
 {
 Log.i（getLocationInfo JSONException，e.toString（））; 
} 
 return jsonObject; 
} 
 
 public ArrayList< Double> getLatLong（JSONObject jsonObject）
 {
 ArrayList< Double> latlng = new ArrayList< Double>（）; 
 
 try 
 {
 longitute =（（JSONArray）jsonObject.get（results））。getJSONObject（0）.getJSONObject（geometry）。getJSONObject（location ）.getDouble（ LNG）; 
 latitude =（（JSONArray）jsonObject.get（results））。getJSONObject（0）.getJSONObject（geometry）。getJSONObject（location）。getDouble（lat）; 
 latlng.add（latitude）; 
 latlng.add（longitute）; 
} 
 catch（JSONException e）
 {
 longitute = 0; 
 latitude = 0; 
 Log.i（getLatLong，e.toString（））; 
} 
返回latlng; 
 
 
 
 $ b现在我们可以在我们的类中调用它
 $ b $ latitude = new GetXMLTask（）。getLatLong（new GetXMLTask （）.getLocationInfo（地址））得到（0）; 
 longitude = new GetXMLTask（）。getLatLong（new GetXMLTask（）。getLocationInfo（address））。get（1）; 
  

我可能没有超级优化的代码，但这对我来说工作得很好，给它一个尝试，只是通过您的调用类中的地址

I'm about to trace with direction service the railway between two station. The problem is I can't get the Lat/Lng of the two station, it get always a neighbour points.

The route is (search on google maps website) :

Ceres, TO to Stazione Porta Nuova, Corso Vittorio Emanuele II, 58, Torino

I need Lat/Lng of Ceres (train station) and Stazione Porta Nuova, Corso Vittorio Emanuele II, 58, Torino (train station). How can I get them?

So I can draw in my maps the same railway (brown line).

解决方案

public class GetXMLTask
{
    static double longitute;
    static double latitude;
    public JSONObject getLocationInfo(String address)
    {
        StringBuilder stringBuilder = new StringBuilder();
        try 
        {
            address = address.replaceAll(" ","%20");    
            HttpPost httppost = new HttpPost("http://maps.google.com/maps/api/geocode/json?address=" + address + "&sensor=false");
            HttpClient client = new DefaultHttpClient();
            HttpResponse response;
            stringBuilder = new StringBuilder();
            response = client.execute(httppost);
            HttpEntity entity = response.getEntity();
            InputStream stream = entity.getContent();
            int b;
            while ((b = stream.read()) != -1) 
            {
                stringBuilder.append((char) b);
            }
        } 
        catch (ClientProtocolException e) 
        {
            Log.i("getLocationInfo ClientProtocolException", e.toString());
        } 
        catch (IOException e) 
        {
            Log.i("getLocationInfo IOException", e.toString());
        }
        JSONObject jsonObject = new JSONObject();
        try 
        {
            jsonObject = new JSONObject(stringBuilder.toString());
        } 
        catch (JSONException e) 
        {
            Log.i("getLocationInfo JSONException", e.toString());
        }
        return jsonObject;
    }

    public ArrayList<Double> getLatLong(JSONObject jsonObject) 
    {
        ArrayList<Double> latlng = new ArrayList<Double>();

        try 
        {
            longitute = ((JSONArray)jsonObject.get("results")).getJSONObject(0).getJSONObject("geometry").getJSONObject("location").getDouble("lng");
            latitude = ((JSONArray)jsonObject.get("results")).getJSONObject(0).getJSONObject("geometry").getJSONObject("location").getDouble("lat");
            latlng.add(latitude);
            latlng.add(longitute);
        } 
        catch (JSONException e) 
        {
            longitute = 0;
            latitude = 0;
            Log.i("getLatLong", e.toString());
        }
        return latlng;
    }
}


now we can call it inside our class by

latitude = new GetXMLTask().getLatLong(new GetXMLTask().getLocationInfo(address)).get(0);
longitude = new GetXMLTask().getLatLong(new GetXMLTask().getLocationInfo(address)).get(1);

I may not have the super optimised code , but this is working pretty fine for me , give it a try , just passed the address in your calling class

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