如何从我的应用中打开缩短的Google地图网址？ [英] How to open a shortened Google Maps URL from my app?

问题描述

我试图打开Goog​​le地图应用以显示地图中的某些地方，每次用户点击某个按钮时，我的应用会打开Goog​​le地图，问题在于我唯一已缩短的Google网址，例如： http://www.goo.gl/maps/XXXXX ;

当用户点击按钮时，我会检查他们是否安装了Google地图，如果他们不是我的将打开Safari，这工作得很好，但我不知道如何去做Google Maps App。

有没有办法打开这个URL Google Maps SDK？我已阅读此页面中的信息 https://developers.google.com/maps/documentation / ios / ，但没有提供有关此案例的信息。

这是我的代码的一部分：

$ b $（

  if（[[UIApplication sharedApplication] canOpenURL：[NSURL URLWithString：@comgooglemaps：//]]）{
 //打开Goog​​le Maps App 
} else {
 [[UIApplication sharedApplication] openURL：selectedPlace.googleMapsLocation]; 
} 
  

谢谢！

解决方案

缩短的网址可能在Google地图iOS sdk网址方案中不受支持。

您可以使用 Google网址缩短器API 将缩短的网址转换回较长的网址。

示例请求：

GET https://www.googleapis.com/urlshortener/v1/url?shortUrl=您可以尝试API缩短后的API请求来自此链接的网址。



从API响应中，您可以获得很长的网址，如下所示： https://www.google.com/maps/@ 37.4249154，-122.0722049,13z
然后，您可以分析变量的经度和纬度，并将它们用于您的中心参数iOS sdk url scheme，例如 37.4249154，-122.0722049 是位置的中心， 13 是缩放，然后您的网址方案将为 @comgooglemaps：//？center = 37.4249154，-122.0722049& zoom = 13

此文档会告诉您有关Google地图iOS sdk url方案的详细信息。

示例代码：

  if（[[UIApplication sharedApplication] canOpenURL ：
 [NSURL URLWithString：@comgooglemaps：//]]）{
 [[UIApplication sharedApplication] openURL：
 [NSURL URLWithString：@comgooglemaps：//？center = 37.4249154， -122.0 722049和缩放= 13&安培;视图=交通]]; 
} else {
 NSLog（@无法使用comgooglemaps：//）; 
} 
  

完整示例代码，用于请求长网址并在Google地图中打开：

  NSURLSession * session = [NSURLSession sharedSession]; 
 [[session dataTaskWithURL：[NSURL URLWithString：@https://www.googleapis.com/urlshortener/v1/url?shortUrl=https://goo.gl/maps/viRnZ&key=YOU_API_KEY] completionHandler：
 ^（NSData * data，NSURLResponse * response，NSError * error）{
 if（！error）{
 if（[response isKindOfClass：[NSHTTPURLResponse class]]）{
 NSInteger statusCode = [（NSHTTPURLResponse *）response statusCode]; 
 if（statusCode！= 200）{
 NSLog（@dataTaskWithRequest HTTP状态码：％ld，（long）statusCode）; 
 return; 
} 
} 
 NSError * jsonParseError = nil; 
 NSDictionary * json = [NSJSONSerialization JSONObjectWithData：data options：0 error：& jsonParseError]; 
 if（！jsonParseError）{
 NSLog（@％@，json）; 
 NSString * longUrl = [json objectForKey：@longUrl]; 
 NSString * pattern = @。*？@（[0-9.\\\-  - ] *），（[0-9.\\\-  - ] *），（[0-9。 \\  - ] *）*。 
 NSError * regexError = nil; 
 NSRegularExpression * regex = [NSRegularExpression regularExpressionWithPattern：pattern options：0 error：& regexError]; 
 if（！regexError）{
 NSArray * matches = [regex matchesInString：longUrl options：0 range：NSMakeRange（0，[longUrl length]）];; 
 NSString * latitude = [longUrl substringWithRange：[[matches objectAtIndex：0] rangeAtIndex：1]]; 
 NSString * longitude = [longUrl substringWithRange：[[matches objectAtIndex：0] rangeAtIndex：2]]; 
 NSString * zoom = [longUrl substringWithRange：[[matches objectAtIndex：0] rangeAtIndex：3]]; 
 if（[[UIApplication sharedApplication] canOpenURL：
 [NSURL URLWithString：@comgooglemaps：//]]）{
 NSString * openURL = [NSString stringWithFormat：@comgooglemaps：// ？center =％@，％@& zoom =％@& views = traffic，latitude，longitude，zoom]; 
 [[UIApplication sharedApplication] openURL：
 [NSURL URLWithString：openURL]]; 
} else {
 [[UIApplication sharedApplication] openURL：
 [NSURL URLWithString：longUrl]]; 
} 
} else {
 NSLog（@REGEX error：％@，regexError）; 
 
} else {
 NSLog（@JSON解析错误：％@，jsonParseError）; 
} 
} else {
 NSLog（@API request error：％@，error）; 
} 
}] resume]; 
  

I'm trying to open the Google Maps app in order to show some places in a map, each time the user clicks a certain button the idea is that my app will open Google Maps, the problem is that the only thing I've is a shortened Google URL, for example: http://www.goo.gl/maps/XXXXX; where the XXXXX changes depending on the location they are watching.

When the users clicks the button I will check if they have Google Maps installed, in case they don't I'll open Safari, this works just fine, but I don't know how to do it for the Google Maps App.

Is there a way to open this URL with Google Maps SDK? I've read the information in this page https://developers.google.com/maps/documentation/ios/, but no information is provided about this case.

This is the part of my code:

if([[UIApplication sharedApplication] canOpenURL:[NSURL URLWithString:@"comgooglemaps://"]]){
     //Open Google Maps App
 }else{
     [[UIApplication sharedApplication] openURL:selectedPlace.googleMapsLocation];
 }

Thank you!

解决方案

Shortened URL probably not supported in Google Maps iOS sdk url scheme.

You can use Google URL Shortener API to convert your shortened url back to a long url.

Sample request:
GET https://www.googleapis.com/urlshortener/v1/url?shortUrl=https%3A%2F%2Fgoo.gl%2Fmaps%2FviRnZ&key={YOUR_API_KEY}

You can try the API request with your shortened url from this link.

From the API response, you can get a long url, something like this: https://www.google.com/maps/@37.4249154,-122.0722049,13z Then you can parse the latitude and longitude to variables, and use them for the center parameter of your iOS sdk url scheme, for example 37.4249154,-122.0722049 is the center of the location, 13 is the zoom, then the your url scheme will be @"comgooglemaps://?center=37.4249154,-122.0722049&zoom=13

This documentation will give tell you details about Google Maps iOS sdk url scheme.

Sample code:

if ([[UIApplication sharedApplication] canOpenURL:
     [NSURL URLWithString:@"comgooglemaps://"]]) {
  [[UIApplication sharedApplication] openURL:
   [NSURL URLWithString:@"comgooglemaps://?center=37.4249154,-122.0722049&zoom=13&views=traffic"]];
} else {
  NSLog(@"Can't use comgooglemaps://");
}

Full sample code to request long url and open in Google map:

  NSURLSession *session = [NSURLSession sharedSession];
    [[session dataTaskWithURL:[NSURL URLWithString:@"https://www.googleapis.com/urlshortener/v1/url?shortUrl=https://goo.gl/maps/viRnZ&key=YOU_API_KEY"] completionHandler:
        ^(NSData *data, NSURLResponse *response, NSError *error) {
            if (!error) {
                if ([response isKindOfClass:[NSHTTPURLResponse class]]) {
                    NSInteger statusCode = [(NSHTTPURLResponse *)response statusCode];
                    if (statusCode != 200) {
                        NSLog(@"dataTaskWithRequest HTTP status code: %ld", (long)statusCode);
                        return;
                    }
                }
                NSError *jsonParseError = nil;
                NSDictionary *json = [NSJSONSerialization JSONObjectWithData:data options:0 error:&jsonParseError];
                if (!jsonParseError) {
                    NSLog(@"%@", json);
                    NSString *longUrl = [json objectForKey:@"longUrl"];
                    NSString *pattern = @".*?@([0-9.\\-]*),([0-9.\\-]*),([0-9.\\-]*).*";
                    NSError *regexError = nil;
                    NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern:pattern options:0 error:&regexError];
                    if (!regexError) {
                        NSArray* matches = [regex matchesInString:longUrl options:0 range:NSMakeRange(0, [longUrl length])];
                        NSString *latitude = [longUrl substringWithRange:[[matches objectAtIndex:0] rangeAtIndex:1]];
                        NSString *longitude = [longUrl substringWithRange:[[matches objectAtIndex:0] rangeAtIndex:2]];
                        NSString *zoom = [longUrl substringWithRange:[[matches objectAtIndex:0] rangeAtIndex:3]];
                        if ([[UIApplication sharedApplication] canOpenURL:
                             [NSURL URLWithString:@"comgooglemaps://"]]) {
                            NSString *openURL = [NSString stringWithFormat:@"comgooglemaps://?center=%@,%@&zoom=%@&views=traffic", latitude, longitude, zoom];
                            [[UIApplication sharedApplication] openURL:
                             [NSURL URLWithString:openURL]];
                        } else {
                            [[UIApplication sharedApplication] openURL:
                             [NSURL URLWithString:longUrl]];
                        }
                    } else {
                        NSLog(@"REGEX error: %@", regexError);
                    }
                } else {
                    NSLog(@"JSON parse error: %@", jsonParseError);
                }
            } else {
                NSLog(@"API request error: %@", error);
            }
    }] resume];

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