GPS坐标精度 [英] GPS coordinates accuracy

问题描述

我有一些GPS坐标数据，最多9个小数点。例子是：

  39.1234567891 -75.1987654321 
  

我需要处理这些数据以获取人员所在的环境。但为了简单起见，我想将100米范围内的坐标视为一个位置。任何人都可以指向任何可以指示我应该舍入多少小数点的参考，以达到此准确度级别。

解决方案

9位数字对于任何长期大地测量应用程序来说都太详细。厘米范围内，并且通常对于GPS设备来说最为准确。

在赤道之后，小数点后的4位数字是11.11m。

3位数是111.11m

（由 earthCircumference / 360.0 计算）<

这通常会产生一个光栅，但由于地球是一个球体，当离开赤道时，两个经度之间的距离会缩小（因数为cos（纬度））两个纬度之间的距离不变。

I have some data with GPS coordinates with upto 9 decimal points. Example of this is

39.1234567891 -75.1987654321

I need to process this data to get a context of where the person is. But I want to treat the coordinates encompassed within 100m as a single location for simplicity. Can anyone point to any reference that would indicate how many decimal points I should round off to get to this level of accuracy.

解决方案

9 digits is too detailed for any but a long term geodetic app.
6 digits is in centimeter range, and usually the most accurate what makes sense for a GPS device.
At equator 4 digits after decimal point is 11.11m.

3 digits are 111.11m

(Calculated by earthCircumference / 360.0)

This would normally result a raster, but since Earth is a sphere, the distance between two longitudes shrinks when moving away from the equator (with a factor of cos(latitude)) the distance between two latitudes does not change.

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